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Consider the circuit below, solve for average power dissipated in the capacitor and resistor for capacitor impedance -;12, -3

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Given circuit c 12 R Xc = jm. ;-jzn ;-jar macrois capactor. Voltage dissipated : 120. X Vca I+Xc resistor acros! Voltage diss2 Pe 12ox Xc 는 1+Xc Xc 2 PRE 10. (0) - 1+Xc When Xc= -ju :- 104 (w) al X Pet (in 2. (0.707) Р. = 0.499 W PR ILOX - X I- 10.When Xc = -j22:- 2 Pc X 120x (-32) 1-82 -10 2 D. 89 X PL 0.24 V 2 120 X (1) PR - 1 - 32 2 و ] 0.44 : ] PR 0.19. W -53 л WhenPR 120 X (1) = * 1-33 3 1 2 [ 0.36) PR E 0.699 w Plot of in resistor over the power v dissipated impedance: capacitiveلیا ost 10.699,-) ou 03 0.2 (0.19,-23) (0.099,-3) 0:1 Lij -2j - 3j -uj

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