Question

The circuit shown below represents two power supply rails of a circuit board fitted with TTL components (rise time = 10 ns). The DC supply current for each rail is as shown. Measurement of interference on these rails has indicated the presence of capacitive cross-talk. It is observed that 0.75 V, 10 ns rise time transients on the 10 V rail are inducing similar rise time impulses of 150 mV on the 5 V rail. Calculate the value of the coupling capacitance. DC = 10 v, 100 mA Transient amplitude = 0.75v DC = 5 v, 100 mA le ? pF Induced transient amplitude = 0.15v

Answer 1

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Inoluced transient amplitude 0-15V Solution DC-lov, lema Transient amplitude = 0.75 V c-2PF DC = 5V, looma network, electrical tuke equenaleht we can RI W lov R₂ 5v ve (t) = (0.75 -0.15) v = 0.6V i R = 10 100x10-3 = 0.1 x 1032 = 0.1KR 100x 10 3 = 0.05x1032 0.05k2

de voltage is applied cele NOW at steudly botate 4 nove cehen Capacitor aces open arcuit. os Ri 10V => Jov A T Pov 5v ve (0)= (105)v 5 V V(0-) = Ov= initine voltage voltage across cupucitance we knout, Velt) = Ve(o) +[vc (o)- - vc (*) je tla T= time constant constant = Rea c = (P +R2) C (0.1 +0.05) x103 x 0.158 183xC

% Vel&I= YeCo) + [Veco)-Vela)]e-女に w06 : 5+[0-5]etc 5(ine-kle) sl 012=1e-C 2106 一女 0.82:e 一01278=一女 で 01278%3D 10010-9 で 10x10-9 01278 as Q1GX103xe = 7-824X10-8

0-15x10 3 xC = 7.824X10-8 C = 0.5216 x 10-9 F C 521-6 x 10-12 F si C = 521.6 PF