Question

Q1.Calculate the current I by superposition. 44 Чл 3r 128v 16 1 3oi, - 5.2 Q2.Calculate the current I by superposition. 54 122 2011 400 2532 you 7.5 A Ҷол Q3.Calculate the current I by successive source transformation. 54 12.02 1 2012 400 252 40S 7.5 A V 402 Q4.Calculate the current I by successive source transformation IA 52 17e 2A بائی '1.52 34v

i need q1 q2 q3 q4 please without anymistakes

Answer 1

YA iz 44 3л. + 1280 bu 30ix I 2n sn Using Superposition theorem: Consider only voltage sovice ix Vx ix = 128-vx 4+2 Kclat node be: ier 3 #1281 sor 3012 SN Vx 128-VX + VX-301x 3+5 6 4+2 substitute ② 128 - V 0., - - (129-11) Va (***** + a) = (2x + 30112* V₂ = 93.54 I'= Va 6 93.54 15:59 A. 215-6 A Consider only convient source: YA чл. M اچ 1"=2-13 YIT 3.1 3oin ia 361 ул. 2.1

2 KUL: By Love 1 = А Зэр ча-ін) +6 (12-13 ) tab = ? – чі, + +2", – біз =0 loop 3 kuli 6 (13-12 ) + 3 (13-1) +3oix +53 -0 but ix= 12-4. - 31 — 62 + Jч із + 30 (1а -4) = 2.0 - зі+ ачір +14 і 3 Soluing 0, 0,6 irrч , = 3.356 , iz = 3-846 Now T" - і - з = 3- 4S 6 - 3 896 Т" -- 646 А. MS- 3. Т' + т1 т 1S6 — on 6 т с 15 А

SA 022 I 2on 12 you 1/7-5A You .8252 40 V Sance: consider only I' 12 20m 40V you 25 I Il 12 127 6on 40V 251140 you 11 25 X 60 251160 17.65 25160 I'- -40 12+17.65 2.-1035 A .

Consider SA source SA 12 201 25 OV yor 2005 IDOV Ve 1+ 201 21 (25 34OV kci at node Uxi Vx 12 Vx 25 Vit100 20140 -100 vill ta žo + to) - Vu (0.14) --)1.9 V -C=109) = 0.9424 12 12 Consider. 7.5A Source I!!! M-> 12 20 325 7.5A 740

12 7,5X40 - 2007 as 340 kal at by: + Vy Vy-300 12 as Yotao Vy++) 360 .60 y = 35.7 I'' -vy -35. la -2.995 A 12 Now I = I'+ I" + 11 -1.35 +0.992-2.975 -3-333 A SA 93) 122 1 20 } you 925 1)-SA You Using Sourze transformation SA + 2 on M 20x5 =100V 20

чол. Чом E) 1)ars A 1:Xчо - 200 100V T + 12 сар о чол. 25. Чои Зооо 12 Т. бол HOV SAE 4 т Зоо - Госз 2од и т 12 во Чу + zas (+) 2-ооу Т. 12 you t <as гол оо Go 333 А as || 60 25х6 -17-6s 25 to

T 1 E)чун 11.6S 13-334 12. 12:45 140V Тә:4SX 333 E5B 77S. 1 — Чо -58-77s - 3 •33 А | |R+7 65 12- 333 А Q4) 1 su ја Л. 1 ел 2) 5 - S зч XS-SV т 1 - Сл Кл Sh. 2х4 S17 1:5 34 ја =2A ај 20 1ə|| IS (а) 1:s = 17XI-S • 318 л. 11+).

I 6 on sn Lå 1378 12v I 5V 1 + son + 12V 72x13378= 2.756 V 81-378 I 12+5+2.756 6+6+5+13378 I = 1,075 A .