Question

I need answers only please I don't want many clarifications please

Q1.Calculate the current I by superposition. ЧА Чл 18 3л 6. (І - 5L "х -

Answer 1

Soln: - 4A M x 4.0 128V 6n goix I 22 5n Considering 128V Source alone mis 3r 40 128V© 23 3ojх 20 I' wwt AM 2r Śn ix+1) KUL in loop 1 -128 + fix + 6 I' +2 ix 20 > -128 + 6ix+61'- 0 (1) '

KUL in loop II 3 ix-I')+30 1x + s (x-I')-61'=0 N IN 381x-14I.za ix141 I I 38 19 substituting in (0) --128 + 6 I' +6XIIZO 19 156 Il-128 19 ラ I', 19X128 156 37A = 434280 608 15.589 A 39 Considering 4 A source alone 4A mus 4 nix Es istý (ix+4) es Bar 21 30ix Yix-I'+4) Rr

Applying KvL in loop I, fix +60' + 2 cix+4)0 6ix x + 6 I" + 8zo (in) Applying KUL in loop II 3 Cix - I") +30 ix +5lix -I"+4) - 6I"_0 38 ix -14 I" +20 =0 cilj solving cij and vi simultaneously jx -29 I" -23 A 39 А 39 From superposition theorem, I'+I" I z 608 23 15 A 39 39 585 39 = 15 A