Question

Q2.Calculate the current I by superposition. 5A 122 2or 40v 252 'you 7.5 A tv You

Answer 1

the Circuit as Solution) We are given Shown and we are required find the worent. I to 5A 122 I M 20.2 4or w 7 40V + 252 7.5A Slepi ciscuiting open and un Hou all Cuorent Bowries sowie ; voltage I 2012 w finding this, current for 122 w 402 40 8252 + 140V I= Veg Req Reqa 12 + 25 11 (20+40+40) Req win 402 32R 12 + 25 x 100 125 > I, = 40 32 =1:25 A but as direction is opposite this, I = -1.25 A circuiting Step 2 = Now find current by 5A sowne by open circuiting 7.5A sowue and shost thus, we get Ia HOV So wue. ad

2001 122 applying sourne parallel weget this looksourue in 100 V 2 100 V L I 2 5A Now AAN w source 402 252 transformation und as SA so wrie & 402 202 care in par V= 20x 5 = Series with 20 r. IZ 20.2 TAMM wit - V. 1212 25.2 R. www where V=100V Hor and RE 40+40 + 251112 + 20 100 t 25x12 = 108.1082 37 I = 100 0.925A N Now applying 108.108. Current divider I g = 12.33 x 25 37 0.625 A Werent for 75A sowie t ciranti this, I 2 = Hor π S 3 = Step 3 & Now finding 5 A source Iz lar xor MW mun A Now, applying hor 252 72 7.5A Source transformation, ww V= 7.5 x 40 40.2 = 300V thus, Circuit becomes

20.2 wir Iz sor thus I=/ R Eur 402 225-32 +) 300 V R- 40+20+ 251112 402 THO =100+ 8.108 108.108 = 2.775 A 5 I = 300 108.108 (worent diceder) thus Iz = 2.775 x 25 37 1.875 A a. I, IS 2 A -1.875 opposite Iz oo total Current H 2 Ijt Ig +I3 = -1.25 +0.625 -1.875 :-2.5 A required Thus, the current is -2.5A = I and solved by superposition theoxen Clae solved by taking individual component effect and doing algebric Sum)
​​​​​​​Therefore required value was calculated out using superposition thereom and each step was well explained