Answer : Among the above given steps the step shown as follows is not a possible termination step in the free radical chlorination of methane which is shown as follows :
(D) .CH3 +
Cl2
CH3Cl + Cl
This is due to the fact that, as we know, during chain termination step in the free radical chlorination of methane two free radical combine together to form neutral molecule such as two .CH3 free radical combine to form CH3-CH3 (as shown in C); two .Cl free radical combine to form Cl2 ; .CH3 free radical combine with .Cl free radical to form CH3Cl (as shown in B).
And step shown in (D)
.CH3 +
Cl2
CH3Cl + Cl is chain propagation step in the free radical
chlorination of methane instead of the chain termination step.
Thus, (D) .CH3 +
Cl2
CH3Cl + Cl is not a possible termination step in the
free radical chlorination of methane.
Which of the following is not a possible termination step in the free radical ? chlorination...
Which of the following is a chain propagation step in the free
radical chlorination of methane?
Which of the following is a chain propagation step in the free radical chlorination of methane? A) CH4 +CI-CH3 + HCI B) CI+ CH3 -CH3CI C).CH3 + CH4-CH4+ CH3 D) C12-21
Which of the following is cannot be considered an initiation or propagation step of a free radical reaction of an alkane? O A. Cl. + CH4 → HCI + CH3. OB. CH3. + Cl2 → CH3CI + CI. OC. CH3. + Cl. → CH3CI OD. C12 → 2C1. O E. CH3. + CH3C1 → CH4 + CH2CI.
help with page
23. How is the following step in the free radical chlorination mechanism described *CH3 + 'Cl → CHCI a. initiation step b . termination step c. propagation step d. electrophilic step 24. Which compound would give the following alkene as the major product in an elimination reaction with CH3CH2ONat? ? CHỊCHONa. Br Br 1 3 a. 1 b. 2 c. 3 d. 1 and 3 25. What is the product of the following reaction? OH H2SO4 он...
Ho for the pre c! . Given the bond dissociation energies below in Kcal/mol, estimate the ano forth (CH),CH-CI step . CHCI c) 40 kcal/mol (CH.J.CH a) +22 kcal/mol b)-22 kcal/mol e) -45 kcal/mol he major monobrominated product that results from when methylcyclopentane is subjected d) +45 kcal/mol c) a tertiary halide radical bromination is b) a secondary halide e) bromomethane a) A primary halide d) A quaternary halide 3. Which of the following is a termination a) Cl +...
pleas help 5,6,7,8,9,10
III IV 5. The product of free-radical halogenation reactions is an alkyl halide. The major amount of this halide forms during the second step of propagation. However, you should be aware that one possible termination step also forms alkyl halides. Why does the majority of the alkyl halide product come from the propagation step and not the termination step? A. At any given time during the reaction, the concentration of both the alkyl radical and the halide...
a) Show the mechanism for the free radical chlorination of
bromopropane. Clearly show the initiation, propagation, and
termination steps.
b) Use the BDEs shown on page 1 to calculate the enthalpy change
for this reaction.
c) Unfortunately, the student’s attempt in question 3 failed,
and he only made traces of 2- chloropropane by using this approach.
What was the major product of the reaction, and explain why it was
formed instead. You may find the BDEs on page 1 to...
Which of the following compounds cannot undergo free radical chlorination? Propane Benzene Cyclopentane Octane Methane
propose a mechanism for the free-radical chlorination of ethane. ch3-ch3 + cl2 +hv ---> ch3-ch2cl + hcl
7. The free radical reaction step depicted below is best classified as a. Initiation c. Termination d. Regeneration 8. Which of the following IUPAC names correctly identifies the molecule shown below? a. (1R3S)-1-fluoro-3-ethylcyclopentane d. e. (1R,3R)-3-fluoro-1-ethylcyclopentane (1R,3S)-3-fluoro-1 None of the above 9. For the reaction coordinate shown below, which step of the reaction mechanism is the rate determining step (RDS)? reaction coordinate a. Step 1 b. Step 2 c. Step 3 d. Step 4 10 A molecule contains four chiral...
1) In the reaction of Cl2 with ethane and UV light, which of the following reactions would be a chain termination event(s)? 1) Cl. + CH3-CH3 CH3-CH2-CI+H. II) CI+ CH3-CH3 CH3-H2C + HCI III) Cl. + CH3-H2C: CH3-CH2-CI IV)Cl2 + CH3-H2C CH3-CH2-CI+ CI: V) Cl2 + UV light - CI+CI- A) reaction V B) reactions I and IV C) reactions III and IV D) reactions I and II E) reaction III 2) Given the chlorination of acetone shown below.choose the...