Which of the following is a chain propagation step in the free radical chlorination of methane?...
Which of the following is cannot be considered an initiation or propagation step of a free radical reaction of an alkane? O A. Cl. + CH4 → HCI + CH3. OB. CH3. + Cl2 → CH3CI + CI. OC. CH3. + Cl. → CH3CI OD. C12 → 2C1. O E. CH3. + CH3C1 → CH4 + CH2CI.
Which of the following is not a possible termination step in the free radical ? chlorination of methane A. -CH3 + wall → CH3-wall B. CH3 + Cl. → CH3CI C. CH3 + CH3 – CH3CH3 D. CH3 + Cl2 → CH3Cl + CI E. CI + wall → Cl-wall
Shown below is an alternative mechanism for the photochemical chain radical chlorination of methane: Cl_2 + CH_4 right arrow CH_3CI + HCL Step 1 (initiation): CI_2 right arrow 2CI- Step 2 (propagation, part 1): CI +CH_4 right arrow CH_3CI + H Step 3 (propagation, part 2): H + CI_2 right arrow HCI +CI. Using the data provided below(bond dissociation energies, BDE), calculate delta Hdegree for each of the two propagation steps of the alternative mechanism. BDE: C-H bond, 104kcal/mol; C-Cl...
help with page 23. How is the following step in the free radical chlorination mechanism described *CH3 + 'Cl → CHCI a. initiation step b . termination step c. propagation step d. electrophilic step 24. Which compound would give the following alkene as the major product in an elimination reaction with CH3CH2ONat? ? CHỊCHONa. Br Br 1 3 a. 1 b. 2 c. 3 d. 1 and 3 25. What is the product of the following reaction? OH H2SO4 он...
Which of the following compounds cannot undergo free radical chlorination? Propane Benzene Cyclopentane Octane Methane
a) Show the mechanism for the free radical chlorination of bromopropane. Clearly show the initiation, propagation, and termination steps. b) Use the BDEs shown on page 1 to calculate the enthalpy change for this reaction. c) Unfortunately, the student’s attempt in question 3 failed, and he only made traces of 2- chloropropane by using this approach. What was the major product of the reaction, and explain why it was formed instead. You may find the BDEs on page 1 to...
pleas help 5,6,7,8,9,10 III IV 5. The product of free-radical halogenation reactions is an alkyl halide. The major amount of this halide forms during the second step of propagation. However, you should be aware that one possible termination step also forms alkyl halides. Why does the majority of the alkyl halide product come from the propagation step and not the termination step? A. At any given time during the reaction, the concentration of both the alkyl radical and the halide...
Standard heats reaction values are given for the first three primary mechanistic steps in the free-radical chlorination of methane. Explain why the -105kJ/mol overall standard heats of reaction value for the reaction does not include the standard heats of reaction value for the initiation step, but instead is the sum of the standard heats of reaction values for the two propagation steps. A. Standard heats of reaction (delta H degree) values are given for the first three primary mechanistic steps...
a. Draw the first propagation step for a bromide free radical and the double bond of 1-methylcyclohexene. HINT: One electron from the double bond interacts with the bromide free radical to form a new bond. The other electron from the double bond attaches to one of the carbons. Be sure to use three single-headed arrows, and don't forget to draw the two possible free radical products that will form from this step. Circle the most likely product and explain why...
the answers i circled are incorrect except for number 10. i know number 8 is d. for those two can you explain why the answer is that? can you give me the correct answers and explain why? ren with Down Syndrome waren with local deve we described as generat ) lam towan l and e ch rochemical court of Th correct configuration? is RS). Which offi ces corresponds OH OM HOCH,HOH I WHER TNH, CH, HO CH, w AT 111...