Question

could someone help me figure out how to do these pleaseeee

A female fruit fly who is heterozygous with the phenotype gray body, red eyes & long wings is crossed with a male who is homozygous recessive (black body, purple eyes, vestigial wings). The observed offspring are shown below: # offspring, body color. eye color. wing length 411 gray red long 61 gray red vestigial 2 gray purple long 30 gray purple vestigial 28 black red long black red vestigial 60 black purple long 412 black purple vestigial 1 What is the map distance between body color and eye color? [units] mu (answer to 1 decimal place)

Answer 1

A female fruit fly who is heterozygous with the phenotype gray body, red eyes & long wings is crossed with a male who is homozygous recessive (black body, purple eyes, vestigial wings). The observed offspring are shown below: long # offspring. body color. eye color. wing length 411 gray red 61 gray red vestigial 2 gray purple long 30 gray purple vestigial 28 black red long black red vestigial 60 black purple long 412 black purple vestigial 1 What are the phenotypes of the two parental (non recombinant) chromosomes: gray red long black purple vestigial body: eyes: wings find the answers in the below images

A female fruit fly who is heterozygous with the phenotype gray body, red eyes & long wings is crossed with a male who is homozygous recessive (black body, purple eyes, vestigial wings). The observed offspring are shown below: # offspring. body color. eye color. wing length 411 gray red long 61 gray red vestigial 2 gray purple long 30 gray purple vestigial 28 black red long black red vestigial 60 black purple long 412 black purple vestigial What is the map distance between body color and eye color? [units) mu (answer to 1 decimal place) The steps involved in this problem Step: 1: Finding the correct order of genes Step: 2: Estimation of the distnace between the genes 1. Estimation of the distance between the first pair of genes 2. Estimation of the distance between the second pair of genes 3. Gentic map representation with map distance.

The steps involved in gene order determination Step 1: Combination of genes (Viz., ABC / BAC / CAB) from the parental genotypes (Parental genotypes are high in the progeny). Step 2: Finding of the double crossover products from the above combinations. Step 3: Genotypes and its frequencies for inference. If the DCO frequencies from the above combinations matched with observed DCO frequency categories, then those parental combina- tions is the correct cambination. The center gene from the above order will represent the middle gene.

Gray 101) > blava ig Red eyece) > people > people cyren Long wings (1)) Vestiginal wenge (1) As the parents are lugh in frequencies (non-recombinants) the phendypes of all Red gray log and black people vestigial stepil combination : 2 G G R. Matched with Deo X R I + - 1 g frequency Į corrat order the order The estimation of Distance bin geous NO :4 recombinants (sco + D60) X100. Total no. of Prosung Distance in frost pair of gence (bs and R): G R & R 28 r - Ź 30 g

28+30+1+2 x 100 11 6.06% 1005 f -6.06 er Distance bio and I I gones: GRIG Сл R rL g g Gl+GO+1+2 ox10 - 12.33%. look 2.3347 tu genetic maps r + hooberg 12.33207 18.39 coq f Tube map is not drauri On scale.