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Suppose the rod is moving with a speed of 5.0m/s perpendicular to a 0.80-T magnetic field. The rod has a length of 1.6 m and

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Answer #1

The magnetic force on the rod, Fb = B * L * v
Where B is the magnetic field, L is the length of the rod and v is the velocity of the rod.
Fb = 0.80 * 1.6 * 5
= 6.4 N
The mechanical force needed = Fb
= 6.4 N

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