For a horizontal circular curve whose middle ordinate is 30 ft. Find the tangent distance and...
For a horizontal circular curve whose middle ordinate is 30 ft. Find the tangent distance and the external distance knowing that the deflection angle at PI is 40°.
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For a horizontal circular curve whose middle ordinate is 30 ft.
Find the tangent distance and...
HomewUI A circular-horizontal curve to the right has the following characteristics: Δ or l = 8"24...
HomewUI A circular-horizontal curve to the right has the following characteristics: Δ or l = 8"24°00" PI @ Sta. 64+27.46 Dare = 20000" Coordinates of the PI are 1234.56N & 2468.10E R 2864.79 ft The Azimuth of the back tangent is 76 26'30" T = 210.38 ft. (Azimuth from PC to PI) L =420 ft. Draw a sketch and calculate the following: a) The station of the POC b) The coordinates of the PC c) The station of the PT...
Question 5 A circular horizontal curve with radius of 1,430 ft and an intersection angle of...
Question 5 A circular horizontal curve with radius of 1,430 ft and an intersection angle of 14°30' has its point of intersection (PI) at station 572+00. The forward tangent is to be shifted parallel to itself and 10 ft to the left. If the point of curve (PC) remains the same place, what is the radius of the shifted curve? [10] sta 672+00 Pt PC PI' 114 30 10 ft PT PT li 0 not to scale
Referring to the following illustration, a circular horizontal curve has a chord length (C) of 1710.1...
Referring to the following illustration, a circular horizontal curve has a chord length (C) of 1710.1 ft and a deflection angle of 40°. The point of curvature (PC) of the curve is at sta 457+38.5. (The information is applicable to Problems 5 through 6). PI 40° sta 457+38.5 PC PT C . Based on the above illustration, what is the radius (R) for this curve? (2pts)
5. For a horizontal curve, A=82'30', the station of the PC is 6+14.00, and terrain conditions...
5. For a horizontal curve, A=82'30', the station of the PC is 6+14.00, and terrain conditions require the minimum radius permitted by the specifications of, 100 ft. (are definition). Calculate (15 points): a. The stationing of PI and PT, and the external (E) and middle ordinate distances (M) and chord length (LC) for this curve. b. Compute sub-deflection angles and sub-chords to stake out this curve. Use quarter-stations 1251 (Note: In the example we solved together in class, we used...
Example 10-5 Consider the simple horizontal curve given in Example 10-1, with a tangent distance T=...
Example 10-5 Consider the simple horizontal curve given in Example 10-1, with a tangent distance T= 229.27 ft and an arc length L 391.53 ft. If the station of the PI is established as 7 +47.64, find the stations of the PC and the PT
1. Given the following horizontal curve data, answer questions a d. R-800 ft, 30°. BC Station Δ 1...
1. Given the following horizontal curve data, answer questions a d. R-800 ft, 30°. BC Station Δ 14+67.21; a. The curve length for the above horizontal curve b. With a theodolite on the BC, what is the deflection angle from PI to station 16+50? c. What is the chord length from station 15+50 to 16+50? d. Holding the PI at the same point, if the radius of the above was changed to 900 ft, what would the new BC stationing...
6:47 1 4 Search <Back Hw#3-2019.doc 15- 10. A horizontal curve is designed for a two-lane...
6:47 1 4 Search <Back Hw#3-2019.doc 15- 10. A horizontal curve is designed for a two-lane road in mountainous terrain. The following data are known. Intersection angle: 40 degrees Tangent length: 436.76 feet Station of Pl: 2700+10.65 fs- 0.12 e- 0.08 Determine the following. (a) Design speed (b) Station of the PC (c) Station of the PT (d) Deflection angle and chord length to the first even 100 ft station. 15-11. A proposed highway has two tangents of bearings N...
Problem 4. A horizontal curve is being designed through mountainous terrain for a four-lane road with...
Problem 4. A horizontal curve is being designed through mountainous terrain for a four-lane road with lanes that are 10 ft wide. The central angle is known to be 40 degrees, the tangent distance is 510 ft, and the stationing of the tangent intersection (PI) is 2700+00. (a) Find the curve radius using the geometry given. (b) Find the stationing of the PC and PT. (c) What is be the minimum radius for this curve? Use a design speed of...
Problem # 01: Given data: Chainage of First Tangent Point Registration Number (t) Chainage of Poi...
Take the registration number as 4954.
Problem # 01: Given data: Chainage of First Tangent Point Registration Number (t) Chainage of Point of Interscction Registration Number 350 (f) Radius of Simple Circular Curve Registration Number/10 (ft) Required Data: 1. Determine all the elements of simple circular curve i.c., angle of intersection, angle of deflection, tangent lengths, length of the long chord, length of the curve, external ordinate, mid ordinate, and degrce of curve. 2. Chainage of the end of the...
You are charged with determining the Point of Curve, the first non-zero deflection angle (in degrees,...
You are charged with determining the Point of Curve, the first non-zero deflection angle (in degrees, minutes, and seconds and in decimals), and Intersection Angle of a horizontal curve. You are given the PT, which is 84+32.4 STA, the length of the middle ordinate, which is 65.2 ft, and the radius, which is 1,521 ft. Please provide a tidy sketch of all of the values that you need to find.
HomewUI A circular-horizontal curve to the right has the following characteristics: Δ or l = 8"24°00" PI @ Sta. 64+27.46 Dare = 20000" Coordinates of the PI are 1234.56N & 2468.10E R 2864.79 ft The Azimuth of the back tangent is 76 26'30" T = 210.38 ft. (Azimuth from PC to PI) L =420 ft. Draw a sketch and calculate the following: a) The station of the POC b) The coordinates of the PC c) The station of the PT...
Question 5 A circular horizontal curve with radius of 1,430 ft and an intersection angle of 14°30' has its point of intersection (PI) at station 572+00. The forward tangent is to be shifted parallel to itself and 10 ft to the left. If the point of curve (PC) remains the same place, what is the radius of the shifted curve? [10] sta 672+00 Pt PC PI' 114 30 10 ft PT PT li 0 not to scale
Referring to the following illustration, a circular horizontal curve has a chord length (C) of 1710.1 ft and a deflection angle of 40°. The point of curvature (PC) of the curve is at sta 457+38.5. (The information is applicable to Problems 5 through 6). PI 40° sta 457+38.5 PC PT C . Based on the above illustration, what is the radius (R) for this curve? (2pts)
5. For a horizontal curve, A=82'30', the station of the PC is 6+14.00, and terrain conditions require the minimum radius permitted by the specifications of, 100 ft. (are definition). Calculate (15 points): a. The stationing of PI and PT, and the external (E) and middle ordinate distances (M) and chord length (LC) for this curve. b. Compute sub-deflection angles and sub-chords to stake out this curve. Use quarter-stations 1251 (Note: In the example we solved together in class, we used...
Example 10-5 Consider the simple horizontal curve given in Example 10-1, with a tangent distance T= 229.27 ft and an arc length L 391.53 ft. If the station of the PI is established as 7 +47.64, find the stations of the PC and the PT
1. Given the following horizontal curve data, answer questions a d. R-800 ft, 30°. BC Station Δ 14+67.21; a. The curve length for the above horizontal curve b. With a theodolite on the BC, what is the deflection angle from PI to station 16+50? c. What is the chord length from station 15+50 to 16+50? d. Holding the PI at the same point, if the radius of the above was changed to 900 ft, what would the new BC stationing...
6:47 1 4 Search <Back Hw#3-2019.doc 15- 10. A horizontal curve is designed for a two-lane road in mountainous terrain. The following data are known. Intersection angle: 40 degrees Tangent length: 436.76 feet Station of Pl: 2700+10.65 fs- 0.12 e- 0.08 Determine the following. (a) Design speed (b) Station of the PC (c) Station of the PT (d) Deflection angle and chord length to the first even 100 ft station. 15-11. A proposed highway has two tangents of bearings N...
Problem 4. A horizontal curve is being designed through mountainous terrain for a four-lane road with lanes that are 10 ft wide. The central angle is known to be 40 degrees, the tangent distance is 510 ft, and the stationing of the tangent intersection (PI) is 2700+00. (a) Find the curve radius using the geometry given. (b) Find the stationing of the PC and PT. (c) What is be the minimum radius for this curve? Use a design speed of...
Take the registration number as 4954.
Problem # 01: Given data: Chainage of First Tangent Point Registration Number (t) Chainage of Point of Interscction Registration Number 350 (f) Radius of Simple Circular Curve Registration Number/10 (ft) Required Data: 1. Determine all the elements of simple circular curve i.c., angle of intersection, angle of deflection, tangent lengths, length of the long chord, length of the curve, external ordinate, mid ordinate, and degrce of curve. 2. Chainage of the end of the...
You are charged with determining the Point of Curve, the first non-zero deflection angle (in degrees, minutes, and seconds and in decimals), and Intersection Angle of a horizontal curve. You are given the PT, which is 84+32.4 STA, the length of the middle ordinate, which is 65.2 ft, and the radius, which is 1,521 ft. Please provide a tidy sketch of all of the values that you need to find.
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