Question

Write a C program that acquires a sequence of characters from the keyboard. The sequence ends once the user enters the newline character, i.e., hits the ENTER key. The program modifies the entered sequence by: • First replacing every occurrence of the sequence "ch” with the letter "K" • Then replacing all occurrences of the sequence "oo" with the letter "u" . And then replacing all occurrences of the sequence "ee" with the letter "j" and prints the modified version on the screen. Example: The user enters: abchdefgoohkee The output of the program will be: abkdefguhki

Answer 1

C program for this problem is --

#include <stdio.h>
int main()
{
char a[30];
int i=0;
printf("Enter the string : ");
scanf("%s", a);
printf("Output is : ");
  
while(a[i])
{
if(a[i]=='c'&& a[i+1]=='h')
{
printf("k");
i=i+2;
}
else if(a[i]=='o' && a[i+1]=='o')
{
printf("u");
i=i+2;
}
else if(a[i]=='e'&& a[i+1]=='e')
{
printf("i");
i=i+2;
}
else
{
printf("%c",a[i]);
i=i+1;
}
}
  
return 0;
}

9 Run Debug Stop Share Save {}Beautify Language C main.c 1 { { } #include <stdio.h> 2 int main() 3 - 4 char a[30]; 5 int i=0; 6 printf("Enter the string : "); 7 scanf("%s", a); 8 printf("Output is : "); 9 10 while(a[i]) 11 12 if(a[i]=='c'&& a[i+1]=='h') 13 14 printf("k"); 15 i=i+2; 16 17 else if(a[i]=='o' && a[i+1)=='0') 18 { 19 printf("u"); 20 i=i+2; 21 22 else if(a[i]=='e' && a[i+1)=='e') 23 { 24 printf("i"); 25 i=i+2; 26 27 else 28 29 printf("%c", a[i]); 30 i=i+1; 31 32 33 return; 34 } } } { ܢܟ Peturn oz

Run Debug Stop Share A Save {} Beautify input Enter the string : abchdefgoohkee Output is : abkdefguhki ... Program finished with exit code 0 Press ENTER to exit console.