I need help completing the answer the formula's is given for each part. Thank you.
Question (1):
Following values are given in the question:
V = 100V
f = 60 Hz
R = 2 ohm
L = 15 mH = 15*10-3 H
C = 150 F = 150*10-6 F
(a)
So, Xl = L = (2f)L
Xl = 2**60*15*10-3
Xl = 5.65 ohm
Xc = 1/C = 1/(2f)C
Xc = 1/(2**60*150*10-6)
Xc = 17.68 ohm
So,
|Z| = [22 + (17.68-5.65)2]
|Z| = 148.72
|Z| = 12.19 ohm
Phase angle () =
=
=
= 80.56 degrees
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(b)
If we consider voltage as refrence, then voltage phasor V = 1000
So, source current I = V/ Z
I = 1000/12.1980.56
I = 8.2-80.56 A
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(c)
Instantaneous current i(t) = 2 Icos(t - )
Substituting the values in the above expression we get
i(t) = (2)*8.2 cos[(2**60)t - 80.56]
i(t) = 11.59 cos(377t - 80.56) A
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Question (2):
Given in the question
V = 1200
Xl = j0.2 ohm
Xc = -j3 ohm
R = 5 ohm
(a)
Circuit impedance Z = Xl+ (R*Xc)/(R+Xc)
Z = j0.2 + [5*(-j3)]/[5-j3]
Z = j0.2 - [-1.32 + j2.2]
Z = 1.32 - j2
Z = 2.39-56.57 ohm
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(b)
Current I = V/Z
I = 1200/2.39-56.57
I = 50.256.57 A
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(c)
Active power P = VIcos where is the phase angle of the load equal to -56.57 degrees
P = 120*50.2cos(-56.57)
P = 6024*0.55
P = 3318.72 W
P = 3.318 KW
Reactive power Q = VIsin
Q = 120*50.2sin(-56.57)
Q = 6024*(-0.83)
Q = -5027.38 VAR
Q = -5.027 KVAR
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(d)
phase angle = -56.57 degrees
So, power factor cos = cos(-56.57) = 0.55
I need help completing the answer the formula's is given for each part. Thank you. The...
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