b. What is the chance of getting this particular sequence: HHHT? Submit Answer Incorrect. Tries 2/3...

Question

Question

Answer 1

Answer #1

here as events are independent and probability of head or tail on a flip =1.2

hence b) probability of HHHT =(1/2)*(1/2)*(1/2)*(1/2) =1/16

c)P(getting all heads or no heds)=P(HHHH)+P(TTTT)=(1/16)+(1/16)=1/8

Answer 2

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