Question

SECTION A Question A1. A beam is subjected to a 500kN force and a 600kNm couple as shown in Figure QA1. a) Draw the free body diagram of the beam. (5 marks) b) Calculate the reactions at A and B. [15 marks] 500 KN 600 kNm B 5 m 5 m 5 m X Figure QA1 400455 Page 2 of 5

Answer 1

AL. Answers Given data: applied force, 500 KN applied moment, 600 kNm Free body diagram of the beam is shown below, a) 500kn sooxy) Goo kN.m S Rar Brox3 5 5 m 5m 5 m IRAY Ray Figl. and Roy are the Reaction at A and B in vertical direction is the Reaction at fixed Support A in horizontal, because rollar Support RAM Ron =O B is (b) Consider moment about A, EMA=0 (Roy x 10) - 600 - (500 x **5) = 0 Ray* x 10 600 - 2000 - 0 Roy By - 260 KN (1) Force equilibrium, lim y direction ) + Rey = (500x4) +260 = 400 140 kN (^) force equilibrium. (In a direction Rax = 500 x 333 = 300 kN (+) vertical Thus, Reaction at A, 140 kN (in y direction) and 300 kN (in horizontal) Reaction at B, 260 kN (in vertical) and o (in horizontal) Ray Raggi Rag By RAR