4 Al + 3 O_2 = 2 Al_2O_3 If you start with 10 grams of Al,...

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Question

Answer 1

Answer #1

4 Al + 3O2 ---------------> 2 Al2O3

108g 96g 204 g

10g

a)

108 g Al needs--------------> 96 g O2

10 g Al needs ---------------> x g O2

x = 96 x 10 / 108

x = 8.89 g

O2 needed = 8.89 g

b)

108 g Al gives ----------------> 204 g Al2O3

10 g Al -----------------------> y g Al2O3

y = 10 x 204 / 108

y = 18.89 g

Al2O3 produced = 18.89 g

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Answer 2

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