In lab you carried out a serial dilution and calculated the concentration of each solution. Starting...
wame Jayda March Post-lab 22 Dilution and Titration 1. A dilute HCl solution was prepared by adding 5.00 mL of 12.0 M HCl to a 250.0 ml flask. and diluting with water. What is the concentration of the dilute HCl solution?
Five standard solutions of HBr are prepared by serial dilution in which, at each stage, 10.00 mL are diluted to 160.00 mL. Given that the concentration of the most dilute solution is 2.62 × 10−6 M, determine the concentration of the original HBr stock solution.
Serial Dilution Questions 1, Serial dilution Questions: a) (5 pts) Suppose you begin with stock solution of dye that has a concentration of 350.0 mg/L and do the following set of serial dilutions on it: 5.00 mL of stock diluted to a total volume (TV) of 500.00 mL (Dilution 1); 2,00 mL of Dilution 1 is then diluted to a TV of 250.00 mL (Dilution 2); finally, 1.00 mL of Dilution 2 is then diluted to a total volume of...
1. Serial dilution Questions: a) (5 pts) Suppose you begin with stock solution of dye that has a concentration of 350.0 mg/L and do the following set of serial dilutions on it: 5.00 mL of stock diluted to a total volume (TV) of 500.00 mL (Dilution 1); 2.00 mL of Dilution 1 is then diluted to a TV of 250.00 mL (Dilution 2); finally, 1.00 mL of Dilution 2 is then diluted to a total volume of 100.00 mL. Calculate...
9.81 Starting with a 2.00-M stock solution of HCl, four standard solutions (a–d) are prepared by sequentially diluting 10.00 mL of each solution to 250.0 mL. Determine (a) the concentrations of all four standard solutions and (b) the number of moles of HCl in each solution.
1. A series of dilute NaCl solutions are prepared starting with an initial stock solution of 0.100 M NaCl. Solution A is prepared by pipeting 10 mL of the stock solution into a 250-mL volumetric flask and diluting to volume. Solution B is prepared by pipeting 25 mL of solution A into a 100-mL volumetric flask and diluting to volume. Solution C is prepared by pipeting 20 mL of solution B into a 500-mL volumetric flask and diluting to volume....
The concentration of a solution after dilution can be found by: where M1 is the concentrated solution (in this lab, 0.400 M), and V1 is the volume of the concentrated solution placed in the test tube. The V2 is the total volume of concentrated solution plus water added, and M2 is the concentration of the solution after diluting. Tube 1 has 2.00 mL of the 0.400 M Ni2+ solution and 8.00 mL of water added. What is the concentration of...
Answer 3) The concentration of phosphorous in a stock solution is 10.0 ppm. After the dilution by DI water, three new solutions are prepared as shown in the following table. Find the concentration of phosphorous in these solutions. Show all calculation processes to receive the credit. (6 pts) Phosphorous Concentration After dilution (ppm) Solution # Stock Solution (mL) Total Volume After dilution (ml.) 25.00 2.50 1 50.00 2 8.00 250.0 3 50.00
#1) What should be the concentration of kanamycin if a serial 2-fold dilution was done starting with tube 1 and ending in tube 9 with an initial concentration of 100 ug/mL tube # 1 2 3 4 5 6 7 8 9 10 [control] Kanamycin concentration (ug/ml) 100 ? ? ? ? ? ? ? ? 0 growth no no no no no yes yes yes yes yes #2) Culture C has a titer of 2.3 x 107 bacteria/mL. Draw...
Chemistry 2A Lab 13: Solution Calculations Introduction This lab involves sample calculations using various concentration units. This lab will work with the following types of concentration units: % mass, % volume, % mass/volume, and molarity. A solution is the sum total of the solute and solvent. % mass= mass solute mass solution -100 volumesolute .100 % volume- volume solution % mass/volume mass solute volumesolution -100 Molarity moles solute liters solution The dilution of a liquid requires the addition of more...