A horizontal rectangular surface has dimensions 2.55 cm by 3.15 cm and is in a uniform magnetic field that is directed at an angle of 32.5 above the horizontal.
Part A
What must the magnitude of the magnetic field be in order to produce a flux of 4.10x10-4 Wb through the surface?
given that
area of rectangular surface A = 2.55*3.15*10^-4 = 8.0325*10^-4 m^2
angle = theta = 32.5 degrees
magnetic flux = 4.1*10^-4 Wb
from the relation
magnetic flux = BAcos(90-theta)
B = 4.1*10^-4/8.0325*10^-4*cos(90-32.5) = 0.951 T
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