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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receiveIf u = x3 + 2 is substituted into | x2(x2 + 2)?dx, then we have | x2(w)?dx = { v? (x?dx) We must also convert x2 dx into an e

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S x² x2 (2x3+2)da t Step 2 for example 3+2 is part of this integral, and the derivative of x²+2 is 3x?, which is also excepstep, 3 Now then, Jut. I du I u= x3+2 fx36x² + 2) + dx = Jutdu $[4]+C ( u8] + a - 3 Iy8tc 24 put Back u= x3+2 s (21) tc Ans

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