Question

For the following reaction, 14.2 grams of carbon monoxide are allowed to react with 6.06 grams of oxygen gas. carbon monoxide(g) + oxygen(g) -carbon dioxide(g) What is the maximum amount of carbon dioxide that can be formed? g What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? g Submit Answer Retry Entire Group 9 more group attempts remaining

Answer 1

Mole concept.

Given chemical equation Balanced 2 CO(g) + 0209) Acolding 2002c9) 2 mole 2 mole i mole to mole concept 2 Cuung 2(28)g 32g 569 32g 88 g ? Bul-given 14,29 6.06g First we identity limiting so à reagent- one of given amount reactant tanker g I taken x g of Q (g). 56 g co 32g 14.2g co ? saya 32g x 14.2g 8.11 g x = 56g But we given Just 6.06 og so it is limiting reagent. limiting reagent formula is aqc9) 32 g of a 88 g of coalg 6.06g of a ? say y ya 6.06gx 88g = 16.6 g 32 g 16.6g of coz is formed. ,1

Find the excegg те agent it is co " S оо of co 32-8 obo, 6. 064 oko, 9) say 'p Р € S68 x6:06 Р 1) 32 8 Pa 10. (осу о со Bul- we given 14.2g of co (Ч. 24-10-60 ., excess amoul reagent А. 23. S9" } Ж.