Question

4 Convert 2.14 g CuS to moles 1S. Convert 2.57x10 moles ZoO to grams 16. Convert 1.14 x 10 moles of TiCle to atoms 17. Convert 0.927 g NaF to atoms. 18. Use the following balanced reaction to answer the following questions OdN0h (aq) + 2LiOH (aq) → Cu(01h (s) + 2 LiNO, (a) How many moles of LiNO, form if you start with 7.98 x 10 mol Cu(NO)2 a LiOH is in heavy excess? a. b. How many grams of CulOH): form i is in heavy excess? if you start with 0.547 g of LIOH and Cupt

Answer 1

Formula for Moles = weight/Molar mass moles of Cu S = 2.14 g/95.6 g/mol = 0.0223 mol moles of Zn O = weight in gram/81.38 g/mol ZnO weight in grams = 81.38g/mol times 2.57 times 10^-4 mol = 209.1 times 10^-4 g No.of TiCL_4 molecules = 6.023 times 10^23 times 1.14 times 10^-3 = 6.87 times 10^20 molecules No.of Atoms in TiCl_4 = 5 times 6.87 times 10^20 = 34.35 times 10^20 Nof moles of NaF = 0.927 g/41.9g/mol = 0.022 No.of atoms in NaF = 2 times 0.022 times 6.023 times 10^23 = 0.266 times 10^23 atoms Cu (NO_3)_2 aq + 2 LiOH rightarrow Cu (OH)_2 + 2 LiNO_3 No.of moles of Li (NO_3) formed = 2/1 times 7.98 times 10^-3 = 15.96 times 10^-3 moles No.of moles of LiOH is reacted = 0.547g/23.95g/mol No.of moles of Cu (OH)_2 formed = 1/2 times 0.0228 = 0.0114 No.of grams Cu (OH)_2 formed = 0.0114mol