Question

7) A certain freely falling object, released from rest, requires 1.45 s to travel the last 37.0 m before it hits the ground. (a) Find the velocity of the object when it is 37.0 m above the ground. (Indicate the direction with the sign of your answer. Let the positive direction be upward.) m/s (b) Find the total distance the object travels during the fall. 8) A motorist drives north for 35.0 minutes at 69.5 km/h and then stops for 15.0 minutes. He then continues north, traveling 130 km in 1.80 h. (a) What is his total displacement? km (b) What is his average velocity? km/h

Answer 1

sota Time H ) = 1.455 Distance (5)= 37 m. Lets initial velocity is u el sasut +1012 n (104572 37= 011.05) +4198) (1:45) U=_18141 m/ste ) Ars L pirn is downworld of speed 18141mpel to time achieve (67 Now, v=ut cit. 18.91 - 0 + (118) + 17=1,878 Stel Total time of journey (T) = 1,878 +1:45=31328541 so, Total Distance (s) = ut + I at s = /2 x 90 8x (3.328)² 28= 54.24 m) And

6 speed (r) = 69.5 Km/h time (t) = 35 min. = 35 70 = 7hr. Displacomiat Isla Vita 40:54 2 Am Displacent (42) = 120km in t2=118048 (61 Toted Displacement (si=8,+62 = 170.542km 16) Total 1,80 hr. time (E) = (35+15) de 60 t = 2.633 hr da 1. Avg. speed (v) = Totul Diel - 170.542 Totul Time 20633 Tv=64.71 Km Ihr Ans e Please rute the answer