A sample of 20 randomly chosen water melons was taken from a
large population, and their weights were measured.
The mean weight of the sample was 105 lb. and the standard
deviation was 15 lb.
Calculate (correct to one decimal place) 99.5% confidence limits
for the mean weight of the whole population of watermelons.
a. (94.4 lb , 116.6 lb)
b. (93.6 lb , 115.4 lb)
c. (94.35 lb , 115.64 lb)
A sample of 20 randomly chosen water melons was taken from a large population, and their...
A random sample of size 36 is taken from a population with mean 50 and standard deviation 5. Find P( x¯x¯ < 51.5). The weight of a product is measured in pounds. A sample of 50 units is taken from a recent production. The sample yielded X¯¯¯X¯ = 75 lb, and we know that σ2 = 100 lb. Calculate a 99 percent confidence interval for μ.
How large a sample should be taken if the population mean is to be estimated with 99% confidence to within $67? The population has a standard deviation of $893. (Round your answer up to the next whole number.) You may need to use the appropriate table in Appendix B to answer this question.
A simple random sample of 64 observations was taken from a large population. The sample mean and the standard deviation were determined to be 70 and 12 respectively. The standard error of the mean is . . . (hint: enter the answer with one decimal place)
1) A sample of size 25 is chosen from a population. Assume the probability distribution is normal. If the mean of the sample is 80 and the standard deviation is 6, find the lower bound of the 99% confidence interval. Round off to three decimal places. 2) A sample of size 36 is chosen from a population. The sample mean is 50 and the standard deviation is 5. Find the upper limit of the 95% confidence interval for the population...
A study of women’s weights found that a randomly selected sample of 150 women had a mean weight of 147.3 lb. Assuming that the population standard deviation is 19.6 lb., construct a 95% confidence interval estimate of the mean weight of all women. Choose the correct interval from below: Choose one • 10 points (144.211, 150.389) (140.611, 146.789) (144.667, 149.933) (144.163, 150.437)
A simple random sample of 81 observations was taken from a large population. The sample mean and the sample standard deviation were determined to be 165 and 225 respectively. The standard error of the mean is
3. A sample of 20 silver dollar coins is weighed. The mean of the sample is 8.0710 g and the (l point) standard deviation of the sample is 0 0411 g Construct a 95% confidence interval estimate of the mean weight of all the coins 7.6615 g H84746 g 8.0518 g< H <8.0902 g 8.0447 g<p8.0973 g 8.0329 g<p<8.1121 g 4. To determine the weight of plastic discarded by households, a sample size of 62 weights are (l point) measured...
A sample of size 144 drawn from a large population has a sample mean of 47 and a sample standard deviation of 8. What is the? 95% confidence interval for the population? mean? Round to one decimal place as needed.
Twenty-five packages of a dozen extra-large eggs were randomly selected and their weights measured. The mean was 783.4 grams with a standard deviation of 12.1. Estimate the true standard deviation of the weight of the package of a dozen extra-large eggs using a 95% confidence interval. Assume that the distribution of the weight is approximately normal. Show your full work.
QUESTION 12 A sample of size 100 is chosen from a population. The sample mean is 100 and the standard deviation is 15. Find the upper limit of the 95% confidence interval for the population mean. Round off to three decimal places