Question

3. (30 points total) The load from a plant is equivalent to a resistor in series with an inductor as shown. The plant is supp

inductance = .1 H

Line = 20 Ohm (b) How much is the power loss in the line before and after placement of the capacitor?

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Answer #1

200sin(lot) OIH 141.420, from J=Imsinot Vams = = 200- 141-420, W = 10 rad/sec. inductance (t)=01H =) XL=col=1080.1=1 Now theHow Rotal power supplied S power Zeo, reactive S=Vrmsx irms = 141-4220) x (6-137–32.668) 868-737.935 IVA To make the read reaPower loss = 122.85/2489 VA When the Capacitor is added S=p=868 VA = irms= A (1) Walts = 6:1377 A 868 141.42 1 Amps Vrms NowTHANK YOU

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