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What are the line currents, phase and line voltages of the load and source, respectively, for...
In a three-phase balanced wye-wye system, the source is an abc-positive sequence set of voltages with Van = 120 000 Vrms. The per phase impedance of the load is 5 +J60. If the line impedance per phase is 0 0, find the line currents, the line to line voltages at the source, and the line to line voltages at the load. 1. Van 120 0" Vrms ZY = 5+j Va VA neutral
1. The phase voltage at the terminals of a balanced three-phase Y-connected load has an amplitude of 120V. The load has an impedance of 39 + j28Ω per phase. It is fed from a line having an impedance of 0.8 + j1.5 Ω per phase. The Y-connected source at the sending end of the line has an internal impedance of 0.2 + j0.5 Ω per phase. Calculate: a) The three line currents b) The three-phase voltages at the load c) ...
A balanced Y-connected load with a phase impedance of 10 + j 4 Ω is supplied by a balanced, positive sequence Δ-connected voltage source having Vab 208∠0o V. Given that the line impedance is 0.8 + j 0.3 Ω per phase. (i) Construct a single-phase equivalent circuit of the three-phase system. (ii) Calculate the phase currents of the load. (iii) Calculate the line voltages at the load.
1. In a three-phase balanced wye-wye system, the source is an abc-positive sequence set of voltages with Van- 120 20 Vrms. The per phase impedance of the load is 5 +j62. If the line impedance per phase is 0 Ω, find the line currents, the line to line voltages at the source, and the line to line voltages at the load 120 20 Vms 2. In a three-phase balanced wye-wye system, the source is an abc-sequence set of voltages with...
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3- a balanced three-phase Y-Y system, the source is an abc sequence of line voltages is Vab - 300230 V rms. The line impedance per phase is 0.6 +j1.22, while the per-phase impedance of the load is 10 +j1492. The line currents in A is: (a) 9.342 - 25.1 (b) 16.182 - 25.1 (e) 6.232 - 55.1 (d) 3.112 - 25 (b) For the circuit in Fig. the inductor current 1() is (a) 6 A (b)...
A balanced Ý-source with positive phase sequence (V,-200 ej4% yms) is connected to a balanced Y-load with Za (25 +j5)2. 45° 3. Sketch the circuit, labeling all values. Find the three line currents and line voltages a. b.
1.) For a balanced three-phase wye-wye circuit. For a negative or ‘acb' sequence, SOURCE с LOAD a + Van n 5k b If Van = 100 VAC (effective voltage) a. Find the other phase voltages, Von and Vcn, including phase angles. b. Find the Line Voltages, including phase angles. C. If Zy = 5k12, find the magnitude of the phase and line currents. note: review the notes from Wednesday/Thursday on which measurements are phase, line, voltages and currents.
5. The line to neutral voltages of a Y-connected three phase source are given by, The above three phase source is directly connected to a delta connected balanced three phase resistive load. The resistance in each phase is 10 ohms. Calculate the current phasor 0. Answer- 4. Following three loads are connected in parallel across a single-phase source voltage source: Load 1 absorbs 15 kW and 6.667 kvar; Load 2 absorbs 3 kVA at 0.96PF leading; Load 3 absorbs 15...
a) Figure 3 shows a Y-connected source driving a A-connected load. This system has a balanced load where Zs-Zb-Z-50225°2. The polar expression for VLI is 784197e V. From Figure 3, Lu V. Figure 3 i) Determine the load voltages. (3 Marks) ii Determine the magnitude the line currents. (1 Mark) ) Determine the magnitude of phase currents. (1 Mark) iv) Draw a phasor diagram of phase voltages and line voltages. (6 Marks) v) Determine the load currents. 3 Marks)
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A three-phase unbalanced source with the following phase to neutral voltages: 300-120 20090 10ol-30 1001-30 is applied to the circuit of balanced star. The star common point is connected to the impedance of Z, -2j The load series impedance per phase is Z, -10+40j a) The load sequence impednace matrix Zo b) The symmetrical components of voltage. (magnitude and angle) ground through Determine
A three-phase unbalanced source with the following phase to neutral voltages: 300-120 20090 10ol-30 1001-30 is applied...