Question

PRE-LAB PROJECTILE MOTION 1. Solve Equation 6 for the time-of-flight of a projec tile launched horizontally from a height H above the surface on which it lands. a 2H d f 18 mls Ignore air resistance in

Answer 1

the solution for above problem as explained below.

Given that, Projectile launched horizontally from a height H, above the surface. Let, Initial velocity mu_x = mu m/s and a_x = 0 m/s^2 mu_y = 0 m/s and a_y = g m/s^2 Then, S = mu_y t + 1/2 a_yt^2 and S = Hm H = (0) t + 1/2 a_y t^2 H = .1/2a_y t^2 a_y t^2 = 2H \r\n t^2 = 2H/a_y and a_y = g m/s^2 t^2 = 2H/g t = squareroot 2H/g