A point charge q = ?2.3 nC is initially at rest adjacent to the negative plate of a capacitor. The charge per unit area on the plates is 4.3 C/m2 and the space between the plates is 6.2 mm.
a) E = sigma/epsilon)
= 4.3*10*10^-6/8.854*10^-12
= 4.857*10^5 N/c
V = E*d
= 4.857*10^5*6.2*10^-3
= 3.01*10^3 volts
= 3.01 kVolts
<<<<<<<<<<<<--------answer
b) Workdone = q*deltaV
= 2.3*10^-9*3.01*10^3
= 6.923*10^-6J
= 6.923 micro J
kinetic energy = workdone = 6.923 micro J
<<<<<<<<---------answer
a) Potential defference = 4.3*6.2*10^-3/ (8.85*10^-12) =3012425 k V
b) kinetic energy = 2.3*10^-9 *3012.42*10^6 =6.92 J
a) Q =C V
C = epsilon A/d = 1.43*10^-9
V = 3.011*10^9 V
b) K.E = qV = 6.29 J
1) V= E*d= sigma/epsilon*d = 4.3*0.0062/8.85*10^-12
=0.003012*10^12V
2)change in KE= work done = energy stored in capacitor= 1/2*q*V= 0.5*(-2.3*10^-9*0.003012*10^12)
=3.4638Nm
sigma = Q/A
= 4.3*10*10^-6/8.854*10^-12= 4.857*10^5 N/c
V = E*d
= 4.857*10^5*6.2*10^-3
= 3.01*10^3 volts
= 3.01 kVolts
potential difference = Ed
potential difference = 4.3*6.2*10^-3/ (8.85*10^-12) =3012425 k V
b) Workdone = q*deltaV
= 2.3*10^-9*3.01*10^3
= 6.923*10^-6J
= 6.923 micro J
kinetic energy = workdone = 6.923 micro j
A point charge q = ?2.3 nC is initially at rest adjacent to the negative plate...
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