For the reaction 4PCl3(g)⇌P4(s)+6Cl2(g) KA= 240.7 The reverse reaction is P4(s)+6Cl2(g)⇌4PCl3(g) What is the value for Kreverse? Enter a numerical answer only.
For the reaction 4PCl3(g)⇌P4(s)+6Cl2(g) KA= 240.7 The reverse reaction is P4(s)+6Cl2(g)⇌4PCl3(g) What is the value for...
Calculate the value of ΔH° for the following reaction: P4O10(s) + 6PCl5(g) ---> 10Cl3PO(g) P4(s) + 6Cl2(g) ---> 4PCl3(g) ΔH° = -1225.6 kJ P4(s) + 5O2(g) ---> P4O10(s) ΔH° = -2967.3 kJ PCl3(g) + Cl2(g) ---> PCl5(g) ΔH° = -84.2 kJ PCl3(g) + (1/2)O2(g) ---> Cl3PO(g) ΔH° = -285.7 k please explain well i do not understand these kind of problems
Determine the equilibrium constant, Kgoal, for the reaction 4PCl5(g)⇌P4(s)+10Cl2(g), Kgoal=? by making use of the following information: P4(s)+6Cl2(g)⇌4PCl3(g), K1=2.00×1019 PCl5(g)⇌PCl3(g)+Cl2(g), K2=1.13×10−2
Assume the reaction of 118.30 g of P4 in the following reaction to determine the other quantities. 1P4 + 6Cl2 -> 4PCl3 moles of P4 reacting = mol moles of Cl2 required = mol moles of PCl3 formed = mol mass of PCl3 formed = g
For the following reaction, 124 grams of phosphorus (P4) are allowed to react with 496 grams of chlorine gas. P4 (s) + 6Cl2 (g) 4PCl3 (l) What is the FORMULA for the limiting reagent? What is the maximum amount of phosphorus trichloride that can be formed in grams? What amount of the excess reagent remains after the reaction is complete in grams?
Part A Determine the value of the equilibrium constant, Kgoal, for the reaction CO2(g)⇌C(s)+O2(g), Kgoal=? by making use of the following information: 1. 2CO2(g)+2H2O(l)⇌CH3COOH(l)+2O2(g), K1 = 5.40×10−16 2. 2H2(g)+O2(g)⇌2H2O(l), K2 = 1.06×1010 3. CH3COOH(l)⇌2C(s)+2H2(g)+O2(g), K3 = 2.68×10−9 Express your answer numerically. Part B Determine the equilibrium constant, Kgoal, for the reaction 4PCl5(g)⇌P4(s)+10Cl2(g), Kgoal=? by making use of the following information: P4(s)+6Cl2(g)⇌4PCl3(g), K1=2.00×1019 PCl5(g)⇌PCl3(g)+Cl2(g), K2=1.13×10−2 Express your answer numerically.
1A) Determine the value of the equilibrium constant, Kgoal, for the reaction CO2(g)⇌C(s)+O2(g), Kgoal=? by making use of the following information: 1. 2CO2(g)+2H2O(l)⇌CH3COOH(l)+2O2(g), K1 = 5.40×10−16 2. 2H2(g)+O2(g)⇌2H2O(l), K2 = 1.06×1010 3. CH3COOH(l)⇌2C(s)+2H2(g)+O2(g), K3 = 2.68×10−9 1B) Determine the equilibrium constant, Kgoal, for the reaction 4PCl5(g)⇌P4(s)+10Cl2(g), Kgoal=? by making use of the following information: P4(s)+6Cl2(g)⇌4PCl3(g), K1=2.00×1019 PCl5(g)⇌PCl3(g)+Cl2(g), K2=1.13×10−2 1C) For a certain reaction, Kc = 8.28×10−5 and kf= 2.12×10−2 M−2⋅s−1 . Calculate the value of the reverse rate constant, kr, given that the reverse...
Determine the value of the equilibrium constant, Kgoal, for the reaction N2(g)+H2O(g)⇌NO(g)+12N2H4(g), Kgoal=? by making use of the following information: 1. N2(g)+O2(g)⇌2NO(g), K1 = 4.10×10−31 2. N2(g)+2H2(g)⇌N2H4(g), K2 = 7.40×10−26 3. 2H2O(g)⇌2H2(g)+O2(g), K3 = 1.06×10−10 Express your answer numerically. Kgoal = Part B Determine the equilibrium constant, Kgoal, for the reaction 4PCl5(g)⇌P4(s)+10Cl2(g), Kgoal=? by making use of the following information: P4(s)+6Cl2(g)⇌4PCl3(g), K1=2.00×1019 PCl5(g)⇌PCl3(g)+Cl2(g), K2=1.13×10−2 Express your answer numerically. Kgoal =
Part A Determine the value of the equilibrium constant, Kgoal, for the reaction C(s)+1/2O2(g)+H2(g)<-->1/2CH3OH(g)+1/2CO(g), Kgoal=? by making use of the following information: 1. CO2(g)+3H2(g)<-->CH3OH(g)+H2O(g) K1 = 1.40 x 10^2 2. CO(g)+H2O(g)<-->CO2(g)+H2(g) K2 = 1.00 x10^5 3. 2C(s)+O2(g)<-->2CO(g) K3 = 2.10 x10^47 Express your answer numerically Kgoal = ? Part B Determine the equilibrium constant, Kgoal, for the reaction 4PCl5(g)<-->P4(s)+10Cl2(g), Kgoal =? by making use of the following information: 1. P4(s)+6Cl2(g)<-->4PCl3(g) K1 = 2.00 x10^19 2. PCl5(g)<-->PCl3(g)+Cl2(g) K2 = 1.13x10^-2 Express...
According to the following reaction, how many grams of chlorine gas are required for the complete reaction of 27.3 grams of phosphorus (P4)? P4 (s) + 6Cl2 (g) 4PCl3 (l)
Assume the reaction of 60.63 g of Cl2 in the following reaction to determine the other quantities. 6Cl2 + 1P4 -> 4PCl3 moles of Cl2 reacting = ____mol moles of P4 required = _____mol moles of PCl3 formed = _____mol mass of PCl3 formed = ______ g