Option 5 is the right answer.
From compound 1 to 4, forms 5 and 6 membered rings when they undergo intramolecular aldol condensation and the products are quite stable. Compound 5 will form 4 membered ring which is highly strained and is unstable. Hence compound 5 donot give intramolecular aldol condensation reaction on treatment with NaOH.
Answer clicked by accident, not necessarily correct Which of the following molecules cannot undergo an intramolecular...
which of the following molecules cannot undergo an intramolecular aldol condensation when treated with NaOH Which of the following molecules cannot undergo an intramolecular aldol condensation when treated with NaOH
please answer all of the 4 questions What cyclic product is formed in the intramolecular Aldol condensation when the following compound is treated with aqueous NaOH? OT 11 0 0 IV What is the Aldol addition product formed from reaction of the following compound with itself? ++,C#o Cาถวาย 0 0 0 What is the cyclic product formed in the intramolecular Aldol condensation when the following compound is treated with aqueous NaOH? 08 pod od IV OT O II III O...
1) Which of the following molecules would not undergo an aldol condensation with itself? Circle each that apply (3 points) CH, OCH, H 2) How could the following crossed-aldol condensation be performed to obtain the product selectively? Devise a method, and detail what to do in the lab below. Also include a full mechanism. (5 points) S. 7-8 4) Provide a complete, electron-pushing mechanism for the reactions shown below (7 points each) (1) "omo (2) H30 HOCI
34. Which of the following molecules will readily undergo an elimination reaction when treated with NaOCH3? . d. 1 BO
29. Which compounds will undergo decarboxylation upon heating? oll i la llo III IV A) I, II B) II, III C) III, IV D) II, IV 30. What major product is formed when the following diketone undergoes aldol cyclization in base? Eto- EtOH uc de op We were unable to transcribe this image32. Which is the major product of the following series of reactions? Soci, OH OH OH i socl, roh, no. 1,0° , silor 'oi uviin 33. Which of...
11) Provide the structure of the major organic product which results when PhCH2CHO is treated with NaOH 12) Provide the structure of the aldol product that results when 4-methylpentanal is treated with sodium hydroxide. 13) What two molecules were condensed in an aldol reaction to produce (CH3)3CCH-CHCOCH3? 1-4) Predict the outcome of the follovwing reaction. 0 0 NaOH, heat 15) Provide the structure of the ester that would undergo self-condensation to yield the B- ketoester shown below.
QUESTION 1 Which of the following will not undergo an aldol condensation reaction? butanal C 2-methylbutanal C 2,2-dimethylbutanal 3,3-dimethyl-2-butanone QUESTION 2 Which of the following constitutes a difference between an aldol and a Claisen condensation? basic conditions Ctetrahedral intermediate Cenolate ion formation protonation of the intermediate QUESTION 3 The product of an aldol condensation reaction is generally favored if Can unsymmetrical ketone and aldehyde are used Can unsymmetrical ester and ketone are used Cone of the carbonyl partners contains no...
Which of the following compounds is LEAST likely to undergo a mixed aldol condensation with 2-propanone in high yield. OA HCHO о (сHз) ссно осHзсно o Pһсно 1. PhCOCI, AICI: 2. KMnO4, H20 3. Brz, FeBry COH What is the final product in the following quence? 0000
Please show/explain which is the correct answer x. Which carbonyl compound must be used to prepare the following conjugated aldehyde during aldol condensation? a) O c) O d) O ar
Given the following reaction below, answer the following questions. Refer to the labeled carbons in the starting material. Write only the numerical symbol in the space provided, ex. 1 Numbering is not necessarily following IUPAC rules, but used for reference purposes only. igues Intramolecular Aldol condensation su 8c numbering is contiguous from L to R A B • Which carbon became the enolate in the ring formation of product A? • Which carbonyl carbon was attacked in the ring formation...