Question

The rate constants for the bromination of several disubstituted stilbenes are given in the table below J. Org. Chem. 1973, 38, 493-499). Br Bro Br Y k (x 103 l/mol min) 220 OMe OMe OMe Me 114 OMe 45 OMe NO Given that the double bond of stilbene acts as the nucleophile, choose the reasonable explanations for the trend observed among the rate constants. Select all that apply. The nitro group is powerfully electron thdrawing a resonance which will reduce the nucleophilicity of the alkene bond Methoxy group is a powerful activator, so its effect should be larger than the effect of a methyl group which is only weakly activating. A methyl group is strongly activating, so its effect should be smaller than the effect of a methoxy group. hloro group withdraws electron density from the aromatic ring and the conjugated alkene bond. A c Chloro and nitro groups are deactivating groups. The Y substituent is near the alkene R bond, so there could be a steric effect. The chloro and nitro groups are donating the electrons v resonance into the alkene z bond, so the rate constant is smaller than the methoxy and methyl groups.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

♡ The nitro group is powerfully election - withdrawing - Via resonance which will reduce the nucleo hili city of the alleme i

Add a comment
Know the answer?
Add Answer to:
The rate constants for the bromination of several disubstituted stilbenes are given in the table below...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Please help me to find the answer Challenge Problem 08.94 9-Borabicyclo[3.3.1]nonane (9-BBN) is a reagent commonly...

    Please help me to find the answer Challenge Problem 08.94 9-Borabicyclo[3.3.1]nonane (9-BBN) is a reagent commonly used in the hydroboration of alkynes, but it can also be employed in reactions with alkenes. The following table provides the relative rates of hydroboration (using 9-BBN) for a variety of alkenes (J. Am. Chem. Soc. 1989, 111, 1414-1418) : Relative Reactivity Alkenes CH—CHОBU, 1 CH2 CHBu, 2 CH2-CHCH2OMe, 3 CH CHOAC, 4 CH2 CHCH2OAC, 5 сH—CHCH,CN, 6 CH2 CHCH2C, 7 cis-2-Butene, 8 tans-CH,CH,CHСHC,...

  • 5. All electron-donating groups are activating groups and all are ortho-para directors with the exception of...

    5. All electron-donating groups are activating groups and all are ortho-para directors with the exception of substituents, all electron-withdrawing groups are deactivating groups and all are meta directors. A. hydroxyl B. amino C. halogens D. alkoxyl 6. Hydrogen abstraction from the methyl group of methylbenzene (toluene) produces a radical called the radical. A. allylic B. free C. halogen D. benzyllic 7. The stability of benzyllic radicals can be explained by theory. A. resonance B. bond order C. inductive D. molecular...

  • Activating/Deactivating Substituents Below is a list of different substituents and experimental results from attempted electrophilic aromatic...

    Activating/Deactivating Substituents Below is a list of different substituents and experimental results from attempted electrophilic aromatic substitution. PhNR, PHCN PhCHO PhF PhMe PhoMe PhNH Deactivating Activating PhNO, PhSozH Phl PhH PNHAC POH • Is the aromatic ring an [ electrophile / nucleophile ] in these reactions? Which substituents 'activate the ring (i.e. make it more reactive? 0 Alkyl substituents: Activate OR Deactivate o Halide substituents: Activate OR Deactivate o OH, NH substituents: Activate OR Deactivate o carbonyl groups: Activate OR...

  • 1. please check what is wrong. Thank you! Determine the product formed when each compound is treated with...

    1. please check what is wrong. Thank you! Determine the product formed when each compound is treated with Br2 and FeBr3. Drag the atom labels to their appropriate positions. CN Atom labels H H Br Br2 A. FeBr Br H OH OH Br Br. Br2 FeBr3 H H Br Br H Br2 FeBr H1 H Reset T Rank the compounds in each group in order of decreasing reactivity in electrophilic aromatic substitution. CI Decreasing reactivity Rank the compounds in each...

  • please help in all sections asap!! Which type of electron is the highest in energy? An electron in an an...

    please help in all sections asap!! Which type of electron is the highest in energy? An electron in an anti-bonding molecular orbital. An electron in a bonding molecular orbital. An electron in an atomic orbital. O A non-bonding electron. Choose a systematic name for the following compound. 1,4 dimethyl ethyl benzene 1,4 diethyl methyl benzene 1,4-diisopropylbenzene 1,4 dipropylbenzene Answer the following questions. -OR Would you expect the above compound to be aromatic? Yes No Choose the correct explanations for the...

  • Please complete for Tuesday, we will go through the questions and mark them in class. pg 156 - 4.23,...

    Please complete for Tuesday, we will go through the questions and mark them in class. pg 156 - 4.23, 4.24, 4.26 pg 170 - 4.29, 4.31, pg 171-4.36 pg 175 - 4.59 pg 176- 4.74, 4.75, 4.80 pg 177-4.81, 4.82 pg 188- 5.1, 5.4, 5.5, 5.6, 5.11 - Using Table 5.1 pg 198-5.22, 5.25 pg 203 - 5.29 pg 206 - 5.37 pg 209 - 5.39 pg 2.14 5.61 pg 235-6.11, 6.14, 6.16 156 CHAPTER 4 Introduction to Organic Compounds...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT