Question

Problem 5 Determine the wind pressure diagram on the all 4 sides and the roof of the 10-story building shown in image below. Building is located in region with designed wind speed of 140 m/h, wind exposure category D. Assume Kzt=1 and Kd=0.85. Importance factor I=1. On the windward side evaluate the magnitude of the wind pressure every 35 ft. Compute internal pressure assuming building is fully enclosed. Compute base shear and overturning moment due to wind. B A leeward D 140' E wind 140 mph 160 80 H

Answer 1

Given that: 10- stomy building assume each storey height wind-speed - 140m/h. kat = 1 and kd = 0.85. Supontance fractor =1 height of the building - 140' wind fragun diagram (windward) ADHE (windward) and BCAF (leeward.) wind other faces it will be 14 varying fuarabolically Reward / - 14 (eleration) 13 А B (plan.) Each 35 storey height = lydha = 14' wind pressure on face ADHE @ ciary p. 0.00256 v va chil ha) Va velocity hi: height upto which wind po is considered. ha= Total height of the building Here,

wind pressure on wind weard side, P = 0.00256 v 2x1 -0.00256 x 1400 P 50. 176 poff + 35' from top. 2 P2 = 0.00256 x 1402x (140-35) 140 P2 = 37.63 psf Ps:0.66256X140 x 140-+6) Ps= 25.088 psf @ last 140 Py = 0.00256 x 1402x35 140 Py = 12.54 PSE shear due to wind load: T@ 1401 Base PBS = P4 X Area x kat xkd x 1 PBS DBS 12.54% (160x80) x 0.85X1X/ 136 435.2 lbs overturning moment due to wind load : Mo =(P, x area xkat a kdx1)x 4/2 50.176x160x1808 (50.176 x 160 x 80 XIX 0.8581) X(149/2) Mo = 38214041.6 lbeft.