Question 3) The image of the nickel in the figure is 2.84 cm from the lens,...

Question

Question

Answer 1

Answer #1

* U1707 lens formula, Śtent 3) 1 - K = 18 > 1-m = = 3) m = 1 - ( m= Magrafication) Magnification - Image height object heigh

Answer 2

Similar Homework Help Questions

A nickel’s image is twice the diameter of the nickel when a lens is 3.53 cm...

A nickel’s image is twice the diameter of the nickel when a lens is 3.53 cm from the nickel and has a positive magnification. Determine the focal lenght of the lens and draw its ray diagram. Answer in units of cm.
I have the answers but need to see these worked out. Thanks! 11- The nickel's image in the figure has twice the diameter of the nickel when the lens is 2.84 cm from the nickel. Determine the foca...

I have the answers but need to see these worked out. Thanks! 11- The nickel's image in the figure has twice the diameter of the nickel when the lens is 2.84 cm from the nickel. Determine the focal length of the lens. 12- Problem 22.17: An electric catfish can generate a significant potential difference using stacks of special cells called electrocytes. Each electrocyte develops a potential difference of 110 mV. How many cells must be connected in series to give...
The nickel's image in the figure below has four times the diameter of the nickel when...

The nickel's image in the figure below has four times the diameter of the nickel when the lens is 2.74 cm from the nickel. Determine the focal length of the lens. Your response differs from the correct answer by more than 100%. cm

A magnifying glass is held 2.9cm from the nickel. the image is twice as large and...

A magnifying glass is held 2.9cm from the nickel. the image is twice as large and erect. find the focal length of the lens.
2. A telescopic lens consists of a convergent lens of 5 cm focal length and 5 cm in diameter plac...

2. A telescopic lens consists of a convergent lens of 5 cm focal length and 5 cm in diameter placed 4 cm in front a divergent lens of focal length -8 cm and diameter 4cm. In addition, a stop ween the lens 2 em from the convergent lens with a diameter of 3 cm. Determine the aperture stop, the limiting entrance and exit pupils for an object 35 em away from the convergent lens. Find positions and diameters. system. b)...
An object is located 26.0 cm from a certain lens. The lens forms a real image that is twice as high as the object. Wha...

An object is located 26.0 cm from a certain lens. The lens forms a real image that is twice as high as the object. What is the focal length of this lens? Now replace the lens used in Part A with another lens. The new lens is a diverging lens whose focal points are at the same distance from the lens as the focal points of the first lens. If the object is 5.00 cm high, what is the height...

1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm...

1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm tall, 11 2emto right of the lens. a. Determine the position of the object. b. Determine the size of the object. Is the image upright or inverted? Are the object and image on the same side or opposite sides of the lens? c. d. 2 You want to use a lens with a focal length of magnitude 36cm with the image twice as long...
For each of the following descriptions: Draw the 3 principal rays to locate the image. Then, using your drawing Gi...

For each of the following descriptions: Draw the 3 principal rays to locate the image. Then, using your drawing Give the image height in centimeters Give the image distance from the lens in centimeters 7) An object is placed 6 cm to the left of a converging lens that has a focal length of 3 cm. 8) An object is placed 3 cm to the left of a converging lens that has a focal length of 9 cm. 9) The...
When a diverging lens is held 13.0 cm above a line of print, as in Figure 26.29, the image is 5.0 cm beneath the lens. (a) Is the image real or virtual? (b) What is the focal length of the lens?

When a diverging lens is held 13.0 cm above a line of print, as in Figure 26.29, the image is 5.0 cm beneath the lens. (a) Is the image real or virtual? (b) What is the focal length of the lens?

A professor is trying to quickly estimate the focal length of a 2.5 cm diameter biconvex lens. He takes the lens and finds the image of the overhead ceiling lights on his table to be 3 cm below the lens, so he estimates the focal length as about 3 cm.

A professor is trying to quickly estimate the focal length of a 2.5 cm diameter biconvex lens. He takes the lens and finds the image of the overhead ceiling lights on his table to be 3 cm below the lens, so he estimates the focal length as about 3 cm. His student objects that at the focus there should be NO image formed, so this must be wrong. Why can the prof make this approximation successfully?