Question

Exercise 27.1 < 1 of 9 » Constants Part A A particle with a charge of -1.24 x 10-8 Cis moving with instantaneous velocity ✓ = (4.19 X 104 m/s)i + (-3.85 x 104 m/s)j. What is the force exerted on this particle by a magnetic field B = (2.00 T)i? Enter the x, y, and 2 components of the force separated by commas. VO ΑΣΦ Submit Previous Answers Request Answer * Incorrect; Try Again; 2 attempts remaining Part B What is the force exerted on this particle by a magnetic field B = (2.00 T)k? Enter the x, y, and 2 components of the force separated by commas. ΑΣΦ ? >

Answer 1

9= -1.24 x1680 V = (4.19 4.04 mil) { + (-3.85 “ ml) 7 V- 54.19x104 71 V= -3.55x16 j 9.01 - 8 = 10 Tj Part A B = (2007) i tanti re- Force f= q un [4.19x15 72.007 F61.24x10) -3.85X1040 70 all bil (az bz-qzbz) azll be - | a3b, – 9163 las 1l b] la, bą -926, 0-0 F= 41.994075) | 0-0 10-(63.85810*)x 2) ) z from this Fx = 0; fy=0, F = (-10 PXLÕ®) (3-sX101)X2 If x=0]Try =o) F2 = -9.548 x10" ] 10, 0, -9548 x10) N

Part Bi- B = (2.00) 2000k F = q uxk f. Guns (4.198104 rol: (x) Ij (y) 11 a 1 k.(2) l o (+3.55*10*) (2) - 7 f = (-1.24x10%) l o -(4.19x104) X(2) loro y fx = (-1.24 xos) (-3.85 409)x2) Fx = 9.548 X164 NT - fy=(-1.24 x165 (4.19 x204) x() J Fy=-1.04 X163 m) [4=0] et sa evity, frontal on 7.548x16, -1.04xco?, o)