A particle with a charge of ?1.24×10?8C is moving with instantaneous velocity v...
A particle with a charge of -1.24×10^8 C is moving with instantaneous velocity v= (1.49×10^4 m/s)i + (-3.85×10^4 m/s)j.
What is the force exerted on this particle by a magnetic field:
(A) B=(1.40 T)i + (-2.30 T)k and;
(B) B=(1.25 T)i + (2.00 T)j + (3.50 T)k?
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A particle with a charge of ?1.24×10?8C is moving with instantaneous velocity v...
A particle with a charge of ?1.24×10?8C is moving withinstantaneous velocity v? = (4.19×104m/s)i^ +...
A particle with a charge of ?1.24×10?8C is moving with instantaneous velocity v? = (4.19×104m/s)i^ + (?3.85×104m/s)j^ .What is the force exerted on this particle by a magnetic field B? = (2.70 T ) i^? Enter the x, y, and z components of the force separated by commas.What is the force exerted on this particle by a magnetic field B? = (2.70 T ) k^? Enter the x, y, and z components of the force separated by commas.
A particle with a charge of -1.24 X 10C is moving with instantaneous velocity (4.19 x...
A particle with a charge of -1.24 X 10C is moving with instantaneous velocity (4.19 x 10 m/s)i + (-3,85 x 10 m/slj Part A What is the force exerted on this particle by a magnetic field B - 12.20 T)i? Enter the 1, , and components of the force separated by commas. Ή ΑΣΦ N Submit Request Answer Part B What is the force exerted on this partide by a magnetic field B. (220 T) Enter the y, and...
A particle with a charge of -2.30 x 10^-8 c is moving with an instantaneous velocity...
A particle with a charge of -2.30 x 10^-8 c is moving with an instantaneous velocity of magnitude 39.5 km/s in the x-y plane at an angle of 55 degrees counterclockwise fromthe + x axis. A. what is the direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the -x direction. B. what is the magnitude of the force exerted on this particle by a magnetic field with magnitude 2.00 T in...
Exercise 27.1 < 1 of 9 » Constants Part A A particle with a charge of...
Exercise 27.1 < 1 of 9 » Constants Part A A particle with a charge of -1.24 x 10-8 Cis moving with instantaneous velocity ✓ = (4.19 X 104 m/s)i + (-3.85 x 104 m/s)j. What is the force exerted on this particle by a magnetic field B = (2.00 T)i? Enter the x, y, and 2 components of the force separated by commas. VO ΑΣΦ Submit Previous Answers Request Answer * Incorrect; Try Again; 2 attempts remaining Part B...
A particle with a charge of-2.50 X 10-8 C is moving with an instantaneous velocity of...
A particle with a charge of-2.50 X 10-8 C is moving with an instantaneous velocity of magnitude 40.0 km/s in the xy- plane at an angle of 50° counterclockwise from the +x axis. What are the magnitude and direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the (a) -x direction, and (b) +z direction?
A particle with a charge of -1.23 × 10-8 C is moving with instantaneous velocity =...
A particle with a charge of -1.23 × 10-8 C
is moving with instantaneous velocity
= (4.27 × 104 m/s)
+ (-3.79 × 104 m/s).
What is the magnitude of the force exerted on this particle by
magnetic field
= (1.32 T)?
(Give your answer in scientific notation using "N" as unit)
A particle with a charge of -2.50x10-8 C is moving with an instantaneous velocity of magnitude...
A particle with a charge of -2.50x10-8 C is moving with an instantaneous velocity of magnitude 36.5 km/s in the c-y plane at an angle of 55 counterclockwise from the to axis. Part A What is the direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the - direction? O +2 O ty 0 +2 Part B What is the magnitude of the force exerted on this particle by a magnetic field...
5.A particle of charge +2.00 x 103 C is moving with velocity v (1000 m/s)j through...
5.A particle of charge +2.00 x 103 C is moving with velocity v (1000 m/s)j through a uniform magnetic field. The magnetic force on the particle is F = (4.00 N)i-(6.00 N)k. What is B, the z component of the magnetic field (in T)? (A) 1.00 (B) 1.50 (C) 4.00 (D) 2.00 (E) 3.00 (F) 5.00
A particle with charge – 5.20 nC is moving in a uniform magnetic field B= -(1.24...
A particle with charge – 5.20 nC is moving in a uniform magnetic field B= -(1.24 T )k. The magnetic force on the particle is measured to be F = -(3.00x10-7N)+(7.60x10-7N) Part B Calculate the x-component of the velocity of the particle. I ALP * O a ? V2 = Submit Request Answer Part C Calculate the y-component of the velocity of the particle. IVO AQ o ? ปี Submit Request Answer A particle with charge – 5.20 nC is...
Problem 20.08 Part C A particle with a charge of -1.70x10-8 C is moving with an instantaneous vel...
Problem 20.08 Part C A particle with a charge of -1.70x10-8 C is moving with an instantaneous velocity of magnitude 41.5 km/s in the z-y plane at an angle of 49.5 counterclockwise from the +x axis. What is the direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the +z direction? Enter your answer as a counterclockwise angle from the ty axis, in degrees, to three significant figures. Submit Previous Answers Request...
A particle with a charge of -1.24 X 10C is moving with instantaneous velocity (4.19 x 10 m/s)i + (-3,85 x 10 m/slj Part A What is the force exerted on this particle by a magnetic field B - 12.20 T)i? Enter the 1, , and components of the force separated by commas. Ή ΑΣΦ N Submit Request Answer Part B What is the force exerted on this partide by a magnetic field B. (220 T) Enter the y, and...
Exercise 27.1 < 1 of 9 » Constants Part A A particle with a charge of -1.24 x 10-8 Cis moving with instantaneous velocity ✓ = (4.19 X 104 m/s)i + (-3.85 x 104 m/s)j. What is the force exerted on this particle by a magnetic field B = (2.00 T)i? Enter the x, y, and 2 components of the force separated by commas. VO ΑΣΦ Submit Previous Answers Request Answer * Incorrect; Try Again; 2 attempts remaining Part B...
A particle with a charge of-2.50 X 10-8 C is moving with an instantaneous velocity of magnitude 40.0 km/s in the xy- plane at an angle of 50° counterclockwise from the +x axis. What are the magnitude and direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the (a) -x direction, and (b) +z direction?
A particle with a charge of -1.23 × 10-8 C
is moving with instantaneous velocity
= (4.27 × 104 m/s)
+ (-3.79 × 104 m/s).
What is the magnitude of the force exerted on this particle by
magnetic field
= (1.32 T)?
(Give your answer in scientific notation using "N" as unit)
A particle with a charge of -2.50x10-8 C is moving with an instantaneous velocity of magnitude 36.5 km/s in the c-y plane at an angle of 55 counterclockwise from the to axis. Part A What is the direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the - direction? O +2 O ty 0 +2 Part B What is the magnitude of the force exerted on this particle by a magnetic field...
5.A particle of charge +2.00 x 103 C is moving with velocity v (1000 m/s)j through a uniform magnetic field. The magnetic force on the particle is F = (4.00 N)i-(6.00 N)k. What is B, the z component of the magnetic field (in T)? (A) 1.00 (B) 1.50 (C) 4.00 (D) 2.00 (E) 3.00 (F) 5.00
A particle with charge – 5.20 nC is moving in a uniform magnetic field B= -(1.24 T )k. The magnetic force on the particle is measured to be F = -(3.00x10-7N)+(7.60x10-7N) Part B Calculate the x-component of the velocity of the particle. I ALP * O a ? V2 = Submit Request Answer Part C Calculate the y-component of the velocity of the particle. IVO AQ o ? ปี Submit Request Answer A particle with charge – 5.20 nC is...
Problem 20.08 Part C A particle with a charge of -1.70x10-8 C is moving with an instantaneous velocity of magnitude 41.5 km/s in the z-y plane at an angle of 49.5 counterclockwise from the +x axis. What is the direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the +z direction? Enter your answer as a counterclockwise angle from the ty axis, in degrees, to three significant figures. Submit Previous Answers Request...
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