Question

A particle with a charge of -1.24 X 10C is moving with instantaneous velocity (4.19 x 10 m/s)i + (-3,85 x 10 m/slj Part A Wha
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Part A = - 105 x 10 3 Magnetic force on morning change F = q (Ux8) q = -1024 X 10°C ū - (4.19x104 € + (-3,05 x 1023) B = 2:20

Add a comment
Know the answer?
Add Answer to:
A particle with a charge of -1.24 X 10C is moving with instantaneous velocity (4.19 x...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A particle with a charge of ?1.24×10?8C is moving withinstantaneous velocity v? = (4.19×104m/s)i^ +...

    A particle with a charge of ?1.24×10?8C is moving with instantaneous velocity v? = (4.19×104m/s)i^ + (?3.85×104m/s)j^ .What is the force exerted on this particle by a magnetic field B? = (2.70 T ) i^? Enter the x, y, and z components of the force separated by commas.What is the force exerted on this particle by a magnetic field B? = (2.70 T ) k^? Enter the x, y, and z components of the force separated by commas.

  • At some time, a charged particle with q = −1.24×10−8C is moving with instantaneous velocity v...

    At some time, a charged particle with q = −1.24×10−8C is moving with instantaneous velocity v = (4.19×104m/s) i^ + (−3.85×104m/s) j^. A. The particle is in a magnetic field B = (2.40 T ) i^. What is the force on the particle? Enter the x, y, and z components of the force separated by commas, so your answer should be three numbers. B. What is the force exerted on this particle if the magnetic field is B = (2.40...

  • Exercise 27.1 < 1 of 9 » Constants Part A A particle with a charge of...

    Exercise 27.1 < 1 of 9 » Constants Part A A particle with a charge of -1.24 x 10-8 Cis moving with instantaneous velocity ✓ = (4.19 X 104 m/s)i + (-3.85 x 104 m/s)j. What is the force exerted on this particle by a magnetic field B = (2.00 T)i? Enter the x, y, and 2 components of the force separated by commas. VO ΑΣΦ Submit Previous Answers Request Answer * Incorrect; Try Again; 2 attempts remaining Part B...

  • A particle with a charge of ?1.24×10?8C is moving with instantaneous velocity v...

    A particle with a charge of -1.24×10^8 C is moving with instantaneous velocity v= (1.49×10^4 m/s)i + (-3.85×10^4 m/s)j. What is the force exerted on this particle by a magnetic field:(A) B=(1.40 T)i + (-2.30 T)k and;(B) B=(1.25 T)i + (2.00 T)j + (3.50 T)k?

  • A particle with a charge of -2.50x10-8 C is moving with an instantaneous velocity of magnitude...

    A particle with a charge of -2.50x10-8 C is moving with an instantaneous velocity of magnitude 36.5 km/s in the c-y plane at an angle of 55 counterclockwise from the to axis. Part A What is the direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the - direction? O +2 O ty 0 +2 Part B What is the magnitude of the force exerted on this particle by a magnetic field...

  • A particle with charge – 5.20 nC is moving in a uniform magnetic field B= -(1.24...

    A particle with charge – 5.20 nC is moving in a uniform magnetic field B= -(1.24 T )k. The magnetic force on the particle is measured to be F = -(3.00x10-7N)+(7.60x10-7N) Part B Calculate the x-component of the velocity of the particle. I ALP * O a ? V2 = Submit Request Answer Part C Calculate the y-component of the velocity of the particle. IVO AQ o ? ปี Submit Request Answer A particle with charge – 5.20 nC is...

  • A particle with a charge of -2.30 x 10^-8 c is moving with an instantaneous velocity...

    A particle with a charge of -2.30 x 10^-8 c is moving with an instantaneous velocity of magnitude 39.5 km/s in the x-y plane at an angle of 55 degrees counterclockwise fromthe + x axis. A. what is the direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the -x direction. B. what is the magnitude of the force exerted on this particle by a magnetic field with magnitude 2.00 T in...

  • A particle with charge - 5.00 nC is moving in a uniform magnetic field B=-(1.24 T...

    A particle with charge - 5.00 nC is moving in a uniform magnetic field B=-(1.24 T ). The magnetic force on the particle is measured to be =-(3.80-10-7N)2+(7.60-10-7N)). Part B Calculate the 1-component of the velocity of the particle. Express your answer in meters per second. | ΑΣφ ? m/s Submit Request Answer Part C Calculate the y-component of the velocity of the particle. Express your answer in meters per second. | ΑΣφ ? m/s Submit Request Answer Part D...

  • Problem 20.08 Part C A particle with a charge of -1.70x10-8 C is moving with an instantaneous vel...

    Problem 20.08 Part C A particle with a charge of -1.70x10-8 C is moving with an instantaneous velocity of magnitude 41.5 km/s in the z-y plane at an angle of 49.5 counterclockwise from the +x axis. What is the direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the +z direction? Enter your answer as a counterclockwise angle from the ty axis, in degrees, to three significant figures. Submit Previous Answers Request...

  • A particle with a charge of-2.50 X 10-8 C is moving with an instantaneous velocity of...

    A particle with a charge of-2.50 X 10-8 C is moving with an instantaneous velocity of magnitude 40.0 km/s in the xy- plane at an angle of 50° counterclockwise from the +x axis. What are the magnitude and direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the (a) -x direction, and (b) +z direction?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT