A particle with a charge of ?1.24×10?8C is moving with instantaneous velocity v? = (4.19×104m/s)i^ + (?3.85×104m/s)j^ .
What is the force exerted on this particle by a magnetic field B? = (2.70 T ) i^? Enter the x, y, and z components of the force separated by commas.
What is the force exerted on this particle by a magnetic field B? = (2.70 T ) k^? Enter the x, y, and z components of the force separated by commas.
A particle with a charge of ?1.24×10?8C is moving withinstantaneous velocity v? = (4.19×104m/s)i^ +...
A particle with a charge of -1.24 X 10C is moving with instantaneous velocity (4.19 x 10 m/s)i + (-3,85 x 10 m/slj Part A What is the force exerted on this particle by a magnetic field B - 12.20 T)i? Enter the 1, , and components of the force separated by commas. Ή ΑΣΦ N Submit Request Answer Part B What is the force exerted on this partide by a magnetic field B. (220 T) Enter the y, and...
A particle with a charge of -1.24×10^8 C is moving with instantaneous velocity v= (1.49×10^4 m/s)i + (-3.85×10^4 m/s)j. What is the force exerted on this particle by a magnetic field:(A) B=(1.40 T)i + (-2.30 T)k and;(B) B=(1.25 T)i + (2.00 T)j + (3.50 T)k?
Exercise 27.1 < 1 of 9 » Constants Part A A particle with a charge of -1.24 x 10-8 Cis moving with instantaneous velocity ✓ = (4.19 X 104 m/s)i + (-3.85 x 104 m/s)j. What is the force exerted on this particle by a magnetic field B = (2.00 T)i? Enter the x, y, and 2 components of the force separated by commas. VO ΑΣΦ Submit Previous Answers Request Answer * Incorrect; Try Again; 2 attempts remaining Part B...
A particle with charge 7.76 x 10-8C is moving in a region where there is a uniform 0.700 T magnetic field in the +x-direction. At a particular instant, the velocity of the particle has components vx = -1.68 * 104 m/s, vy - -3.61 * 104 m's, and 13 -6.35 104 m/s. A. What is the x-component of the force on the particle at this time? B. What is the y-component of the force on the particle at this time?...
A particle with a charge of -2.30 x 10^-8 c is moving with an instantaneous velocity of magnitude 39.5 km/s in the x-y plane at an angle of 55 degrees counterclockwise fromthe + x axis. A. what is the direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the -x direction. B. what is the magnitude of the force exerted on this particle by a magnetic field with magnitude 2.00 T in...
A negative charge q = −3.70×10−6 C is located at the origin and has velocity υ⃗ =(7.50×104m/s)ι^+((−4.90)×104m/s)j^. At this instant what is the magnetic field produced by this charge at the point x = 0.200 m , y = -0.260 m , z = 0? Enter the x, y, and z components of the magnetic field separated by commas.
A particle with a charge of-2.50 X 10-8 C is moving with an instantaneous velocity of magnitude 40.0 km/s in the xy- plane at an angle of 50° counterclockwise from the +x axis. What are the magnitude and direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the (a) -x direction, and (b) +z direction?
Problem 20.08 Part C A particle with a charge of -1.70x10-8 C is moving with an instantaneous velocity of magnitude 41.5 km/s in the z-y plane at an angle of 49.5 counterclockwise from the +x axis. What is the direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the +z direction? Enter your answer as a counterclockwise angle from the ty axis, in degrees, to three significant figures. Submit Previous Answers Request...
A particle with a charge of -2.50x10-8 C is moving with an instantaneous velocity of magnitude 36.5 km/s in the c-y plane at an angle of 55 counterclockwise from the to axis. Part A What is the direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the - direction? O +2 O ty 0 +2 Part B What is the magnitude of the force exerted on this particle by a magnetic field...
solve these 3 question step by step plz Q1. A beam of protons (q 1.6 x 10-19 C) moves at 3.0 x 105 m/s through a uniform 201 alongthe postive z-axis, as shown in the figure. The velocity of each proton lies in the xz-plane and is directed at 30° to the +z-axis. Find the force on a proton. Q2. The figure is a perspective view of a flat surface with area 3.0 cm2 in a uniform magnetic field B....
> Vector Cross Products are wrong.
Nathan Czaja Mon, Nov 8, 2021 5:39 PM