Question

A roofer working on a 30° incline roof drops his hammer. the hammer slides 2.8 m with an acceleration of 1.3 m/s squared along the roof before falling towards the ground

if the hammer lands 3.2 m horizontally from where It left the roof how high is the lip of the roof?

Answer 1

hammer slides on roof from A to B and drops to point c. a veoro conto S=2.8 m - - - Vina - O = 30 - - Ground x=3.2m V- elocity of hammes at point B . Vcore -> horizontal component of velocity Vsino - Vestical 1 . ,

Applying 1st equation of motion along the plane - V₂ = VA + at Applying 3 rd equation of motion along the incline- v²_v² = 2as ? Ve> velocity at B ) I VA velocity at A G VAFO VEV Y an acceleration of hammes V20= 2x 1.3 x 2.8 v2. 2 x 113 x 2.8 = 7.28

V= 7.28 v=2.7 m/s vcoso = V C0830 = 2.7 x S3 2 = 2.33 mles veino = vain 30 2.7 x 1 = 1.35 mle from B to cin Applying 2nd equation of motion horizontal direction - x = Vott 1 at acceleration along horizontal direction is zero, aso Vo = vcoso = 2.33 m/s to time taken to fall ,x= 3.2m 3.2= 2.33xt to t 1.37 sec

Applying 2nd equation of motion in vertical direction from B to C- 2 h= Vot + 1 at? V = Vsino = 1.35 m/s a acceleration is vestical direction a= g = 9.8 m/82 t= 1.37 sec h= (1.35 x 1.37) + 1 x 3.8 X (1137) ha 1.8495 + 9. 1968 m IJs 11.05 m