Question

1. (30 points) Diodes in the circuit below have the cut-in voltage V, -0.7 V. Find the output Vif a) (15 points) 7=1 mA. b) (

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Answer #1

a) FoimA 2 1CA Ass ume boh Canenk flocin orn ane ow and D. and So 52.9 -see +1mA)- -0 S-0-7-216Rl1) -0.7 2tRl) -Sees S-1-4 5-SEa itimA)ESv)-0 No Vo +sv-s-Sen (0-514 mA) zo Vo =5xc0 x0.504 K10 = 2.57 V yO Vo Vo-2-87 at no de Voltose f ahade of dio deSta (G42m4) - (5) - o S-07- 210r(i) -0.7-5kn -1-4 -1(2R4 S(cA)+STO = 0 -i(gentska) - 1.4 P-74 7Kn -O.2m4 -0.PmA DES 01 (G + 2Vo So SE2 2MA) - ESv)o.7v O Vo 10 5-0.7 = O Vo -S-0-7= 0 Vo=S.7 V D. e off Hit Core i valllSo So Valid ON So 1- 2mA wen Vo= S

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