Question

Q1:    20% of the instructions in a program take 1 nsec to execute, 30% take 2 nsec to execute,and the rest take 3 nsec to execute. What is the average execution time per instruction for this program?

Q2: Computer A is 60% faster than computer B. Computer A takes ten seconds to run a program. How long will computer B take to run the same program?

Q3: Computer B is 60% slower than computer A. Computer A takes ten seconds to run a program. How long will computer B take to run the same program?

Q4: 2,500 is how many orders of magnitude larger than 25?

Answer 1

Quest B let total no. of instructions be x. . (0-20*)*! +0-30%)# 2 + (0-50%)* = Total timna 0 20+ 0.60 X + ISO X 2 Total execution time 30.80 X +150% 2 2:30x Total executión time Ariage execution time per instruction - Total time Total instructions 3 2.30 x 22-30 1

oues . We know that performance a L execution REA - PB Er w hese x is the Destesinance (xto 6ox) 10 X EB measure of B: EB 2 16 secs

S PAGE Oress PAA PB EB (*)to 2 (-O-G0X) 10x 2 0.408 EB Er 10 els secs 0.40 Bues 4. 2500 2 25 X (10) ir 2500 is 2 orders of magnitude larger than 25.

Hope this solves your doubt.