solution:-
given that P(Z<0.20)
P(Z<0.20) = 0.5793
by z score standard normal distribution table
Question 23 (1 point) If P1 = 0.33, p 2 = 0.20, and z = 0.20, and your are conducting a hypothesis test with the null hypothesis P1 = P2 by considering the different p1 - P2, then what is SEÇÔ1 - 2)equal to? Note: 1- Only round your final answer to 2 decimal places. Enter your final answer with 2 decimal places
The null hypothesis for a binomial test states that p=0.20. What is the z score for X=5 in a sample of n=100 A) 2.25 B) -3.75 C) -1.5 D) z=2.75
For a standard normal distribution, determine the following probabilities. a) P(z>1.41) b) P(z>−0.31) c) P(−1.81≤z≤−0.69) d) P(−1.80≤z≤0.20)
a. Given that P(A)=0.35, P(B)=0.40 and P(A∩B)=0.20, find P(A∪B) b. Given that P(A)=0.35, P(B)=0.40 and P(A∩B)=0.20, find P(A∩B ̅ ), "the probability of A intersect B complement"
15. If A and B are independent events with P(A) = 0.20 and P(B) =0.50, then P(BA) is: a. 0.20 b. 0.50 c. 0.10 d. 0.70 e. 1.00
b) Assuming the following. P(S)-0.3 P(BIS) 0.75 P(BIS) 0.20 P(HS'B)-0.15 P(H S'nB') 0.9 P(HİSnB)-0.20 Write out the equations and compute: PSPCS) 0.320.1 c) Now eompute the probabilities pertaining to each section in the Venn diagram B2 BnsnH 5 2 3
If P(A) = 0.25, P(B) = 0.35, and P(A intersection B) = 0.20 then, P(A union B) =
P(z>0.23 or z<-0.23) = P(-3<z<O) = P(-0.23<z<2.35) = P(z>1.47 or z<-1.47) = P(z<-2 or z>-1) = P(-3<z<3) -
b) Assuming the following. P(S)- 0.3 P(BIS) 0.75 P(B)S)-0.20 P(HISnB)-0.20 P(H) Sr. B')= 0.8 P(H S'o B)-0.15 Write out the equations and compute: PSnB)- 0.225 c) Now compute the probabilities pertaining to each section in the Venn diagram 5 :5 2 3:(s л н n в": o.odo d) Write out the equation used and compute P(B'n H). e) Write out the equation used and compute P(H) PCH- 0 Compute the probability that it is snowing, given that I made it...
You may need to use the appropriate appendix table or technology to answer this question Consider the following hypothesis test H0: p = 0.20 Ha: p # 0.20 A sample of 400 provided a sample proportion p = 0.185 (a) Compute the value of the test statistic. (Round your answer to two decimal places.) (b) What is the p-value? (Round your answer to four decimal places.) p-value- (C) 0.05, what is your conclusion? 0 Reject H0. There is insufficient evidence...