If P(A) = 0.25, P(B) = 0.35, and P(A intersection B) = 0.20 then, P(A union B) =
P(A union B) = P(A) + P(B) - P(A intersection B)
Substitute given values
=>P(A union B) = P(A) + P(B) - P(A intersection B)
=0.25+0.35 - 0.20
=0.40
If P(A) = 0.25, P(B) = 0.35, and P(A intersection B) = 0.20 then, P(A union...
a. Given that P(A)=0.35, P(B)=0.40 and P(A∩B)=0.20, find P(A∪B) b. Given that P(A)=0.35, P(B)=0.40 and P(A∩B)=0.20, find P(A∩B ̅ ), "the probability of A intersect B complement"
(a) Show that P is closed under union and intersection. That is, show that for all A, B E P AUB,AnBEP (b) Show that NP is closed under union and intersection.
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let A and B be any 2 events with p(A)=0.2; P(AUB)=0.35; P(A
and B)= 0.15 find P(A|B)
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