Question

Here is what i have so far... However i am having a little bit of trouble with it. when inputting a number the sum comes out perfect but when i break the digits up i cant do mmore than 4 digits and i cant do a negitive number... someone help.

QUESTION: Write a program that prompts the user to input an integer and then outputs both the individual digits of the number and the sum of the digits. For example, it should output the individual digits of 3456 as 3 4 5 6, output the individual digits of 8030 as 8 0 3 0, output the individual digits of 2345526 as 2 3 4 5 5 2 6, output the individual digits of 4000 as 4 0 0 0, and output the individual digits of -2345 as 2 3 4 5.

#include <iostream>           // standard input and output libary
#include <iomanip>           // output formating libary

using namespace std;       // use standard namespaces

int main()
{
   int total;
   int i;
   int inputNum;
   int sum;
   int individualNum;

   char ch[4];
   cout << "Enter a number and have it broken into digits: ";       // promps user to input number to be broken into digits
   for (i = 0; i < 4; i++)
   {
       cin.get(ch[i]);
   }

   cout << "the numbers seperate are: " << ch[0] << " " << ch[1] << " " << ch[2] << " " << ch[3] << " " << endl;       // outputs numbers into digits
  
  
  
  
   cout << "Now input number you want the sum for: ";       // prompts user to reinput number to be used to determine total or sum.

   cin >> inputNum;

   inputNum = abs(inputNum); // To handle all negitive numbers so we wont have a problem later.
   total = 0;

   do
   {
       individualNum = inputNum % 10; // To extract the last digit of any number being used.
       total += individualNum;
       inputNum = inputNum / 10; // To remove the last digit og the number being used.

   } while (inputNum > 0);

   cout << "The total of the input number is: " << total << endl;       // outputs sum of the input number

  
     

   system("pause");       // Pause before closing console

   return 0;

}