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Solve Part D please

Learning Goal: To understand how the conservation of energy and Newtons second law can be combined to solve kinetic problemsPart C Using Newtons second law, find vi, the blocks speed at the critical moment when the block leaves the globes surface

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Answer #1

Initial energy of the system,

E = mg(2R) = 2mgR

At the point when the mass loses contact,

E = mghi + 5-mv? + MV

Conserving momentum in the horizontal axis,

MV = mv sin

Given m << M . This implies V<<v .

E = mghi +-mv(v +V sind) mghi + -mv2
Hence,

E = mghi +-mu? = 2mgR

→ghi + = 29R

5 v= V2g(2R - h)

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