C) Easily we
can conclude that the efficiency of nuclear reactors are very much
higher than the coal. Very few amount of Uranium is needed to
produce a large quantity of energy. It is evident from the above
calculations also. Here, 25 gram of Uranium produces same amount of
energy obtained by combustion of 60000 kg of coal. So the
efficiency is much higher in nuclear reactors than
coal.
d) Nuclear fusion is different than nuclear fission. In the fusion, we fuse two or more light weight molecules to a heavyweight molecules. In this process, the mass is lost and the equivalent amount of energy is obtained. But the fusion process itself needs high amount of energy to happen. So generally nuclear fission is done first to occur the nuclear fusion. But nuclear fission is very dangerous to set up in a laboratory. The radioactive waste and the neutron radiation damage are the serious problems. Also the proper coolant is mandatory to convert the thermal energy to the mechanical energy. The moderators are also required to control the nuclear process. All these factors are playing essential roles as the barrier in this process.
digital control Task 1 Find the Z transform of the causal sequence {xx} where Xx = (-1)". 2 Find the Z transform of the causal sequence {xx} where Xx = 4k - 2ak. 3 Find the Z transform of the causal sequences: (a) {k - 3} (b) {3k+2} 4 Find the inverse Z transformation of z? (2-3) F(z) = (22 - 22 + 1)(z - 2)
thats the answer hust need help solving it :)
13. vrix 13. xx
13. vrix
13. xx
If the area to the left of xx in a normal distribution is 0.589, what is the area to the right of xx? Answer: If the area to the right of xx in a normal distribution is 0.589, what is the area to the left of xx? Answer:
xx=50 yy=27 zz=69
Question: 03 (8 Points) Note that xx , yy 12, and zz can be found as follows: If your PMU student ID number is 201502675, then xx = 50 12, yy = 262, and zz = 750 xx zz (Important note: Use your student ID to find the values of xx, yy, and zz as explained above irrespective of the ID digits) Find the current 'I' in the circuit shown in Figure 3. 20 V + 1...
Let XX represent the full height of a certain species of tree. Assume that XX has a normal probability distribution with mean 208.8 ft and standard deviation 32.2 ft. You intend to measure a random sample of n=118n=118 trees. The bell curve below represents the distibution of these sample means. The scale on the horizontal axis is the standard error of the sampling distribution. Complete the indicated boxes, correct to two decimal places.
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Let XX represent the full height of a certain species of tree. Assume that XX has a normal probability distribution with μ=182.9μ=182.9 ft and σ=7.1σ=7.1 ft. You intend to measure a random sample of n=87n=87 trees. What is the mean of the distribution of sample means? μ¯x=μx¯= What is the standard deviation of the distribution of sample means (i.e., the standard error in estimating the mean)? (Report answer accurate to 4 decimal places.) σ¯x= σx¯=
Transaction Filled car with fuel-paid cash Cash sale Invoice sale (R Smith) Date 1 4/3/XX 25/3/XX 3 6/3/XX Amount 32.80 156.99 1.999.00 4 6/3/XX Cash sale 1,899.00 Copy paper-paid cash 5 6/3/XX 6 11/3/XX Filled car with fuel-paid caslh 7 11/3/XX Cash sale 8 13/3xX 11.50 28.50 1.275.00 Copy paper-paid cash 11.50 9 13/3/XX Invoice sale (W Jones) 3.450.00 10 17/3/XXFilled car with fuel-paid cash 31.75 11 19/3/XXCash sale 64.99 12 20/3/XXRent-paid cash 350.00 13 25/3/XXFilled car with fuel-paid caslh...
are 3 (e,m Variables. XX an-Cartng, st.tkyst.t-Budsontaats
are 3 (e,m Variables. XX an-Cartng, st.tkyst.t-Budsontaats
Question 6 xx' = 1 True False