Question

An automobile traveling at 70.0 km/h has tires of 50.0 cm diameter. (a) What is the angular speed of the tires about their axles? rad/s (b) If the car is brought to a stop uniformly in 40.0 complete turns of the tires (without skidding), what is the magnitude of the angular acceleration of the wheels? rad/s2 (c) How far does the car move during the braking? m

Answer 1

Soleno Given or speed of the car=1270km/h Diameter of the five, d= 50 cm . (a) Angulare speed is given by W = = 70 X 10² 60X6ox Soxio =W= 77.7 rad /s . [*v=70km/h ' = 70x10 m/s - 60x60 is Magnitude of angular acceleration of the wheels is given by Lp2=6+220 0=(77.7)+22x40x20 > 1x1 = (77.732 -- 12.017ad/s2 2x40x2A (c) Let the core moves a distance'' during the braking id=or = 40x2** 50 X102 = d = 62.83 m tay