Question

Determine the amount of electric charge q1 in such a way that the resulting force applied to the charge q2 by the charges q1 and 10 microcolone is vertical in the following figure. (The resulting force is zero in the horizontal direction) Then determine the amount of the charge q2 so that the resulting force is five Newton.

92 36 cm 10 uc 91 48 cm 27 cm

Answer 1

we known that 9-10 MC 48 cm 27 cm In the According to the at point B on the Force qe net Force Ez Cosoz = Fez cofo, f other equation is Fiz sin Oz + F3 Sino, =SN-③ In the AABC tm02 = be ton O2 = 36 = 24 10,= 36.60] In the ABCD 1 ton o, = 3 4 5 [0, - 53.13*] we known that For K 2 2 2 In the AABE A B = A²+ Bc? A B = 536² +48²

A B = 3600 [AB = 60cm] => [v1 = 60cm] In the ABCD Bo? = Bc²+ CO² BD" = $36²+ 27² BD = 52025 [BP = 45 cm] = t = asam] So put the volue In the equation 1 Fiz cosO₂ = F 3 coso K2, 22 coso, K% 23 Coso, e o oporto q=(60) * (loxioo cos (33.135 (459) Cof (36081) 2 = 2160xious 1620 = 1.3810S = 13c /

we put the volue In equation & Fiz Sim Os + Fez Sino, =s * 2, 2q Sim Os K22 23 Sino, s » l { my thing ) = 5 8x10x Sin s 3-13x10x10 x108x Sin 36-86* 1. 3x100 60X 60X104 45X45X104 71-79x107 » 7,018 X 109 3600x10-4 + your love that the as 35 202 SX => 22 [19.49204 35. Sovely = 5 = 54.92X10 y = 0.0907 x 104 c (= 9.09 He] So the q, charge volue is = 134c qz chorge volue is = 9.09 MC