Question

A professor created the circuit shown in the figure for her tab. Assuming 83.20 V and R4100, find the following quantities. 12.0V 4.000 w 2.00 . w w R (a) the current in the 2.00 resistor (Enter the magnitude in MA.) MA (b) the potential difference (In V) between points a and be

Answer 1

the Draw the simplified circuit and show the current flowing in all the its brauclus. 12V 427 et th IS IztIZ 2 b ö YIZ un R = 4.80.2 + E-8.20 K.C.L. At point ke will givez- It Is I B Now apply Krichoff's No Hage law (K.V. 2) in loop - I 124 41,- 25,20 A B.20+252 -4.80 Iz 70 From epen A 12-4(In +Iz ) - 21% =0 12 -6 In -U1320 multiply to in een 24.60 +612 adding een and ② by 14:40 I3 co D ; }

36.60-18.40 Iz = 0 In = 36.60 1:9891 amp. 18.40 from een Iz 12 - 411.9091) -0.673 9 amp. 6 in 22 resistor es a) The Curent Iz = 0.6739 673.91 mA b) Na- Vb = 2I2 = 2X 0.6739 1.347826 volts = So, V-Va 11 1.3478 volts