Question

For the circuit shown in the figure below, calculate the following quantities. (Assume -4.00 V and R-8.00 ?. ) 12.0 V 4.00 2 2.00 ? (a) the current in the 2.00-? resistor (Enter the magnitude.) mA (b) the potential difference between points a and b

Answer 1

Your diagram is with ε-4 volt, and R-8 . 2.0 V 4.00 Ω 2.00 2 Your diagram can be simplified as follows 12, V 2-0 a, b,c,d,e,f are the points to help you visualize the procedures I am going to describe ahead 1. Let "" be the current as shown in the figure. [Notice its direction alsol 2. "" breaks up into two branch at point 'c', ii and another is obviously" i 3. By the two arrow signs I have shown the direction of currents in each loops in absence of the voltage source on the other loop For example by the upper arrow sign, I mean that current would flow in the direction of arrow if 4 volt source voltage would not be there.

Now follow the calculation: Appling Kirckkeff's veltngs I law in PPS Tstel soutee voltage in h Loop 8 +2

NOW ** Arrow sign and direction of 11 are anti parallel , that's why-11 is taken instead of + i1 . Negative value of means that our assumed direction of h is wrong and il goes in anti- clockwise direction.

polentint differe es points digaram otential d rte Final Result Current in 2Ω resistor is 10/7 Amp that is 10*1000/7 mA-1428. 57mA. Potential difference between points "a" and "b" is 20/7 V that is 2.86 V (nearly).