Question

For the circuit shown in the figure below, calculate the following quantities. (Assume E = 9.00 V and R = 7.50 ) 12.0 V 4.00 2 Hemo 2.00 w + R E (a) the current in the 2.00-n resistor (Enter the magnitude.) mA (b) the potential difference between points a and b V Additional Materials eBook

Answer 1

a 12N 42 al I 1 (1-1) b 22 a + xhemu E=gv Using Kirchoff's juction rale; Current distribution in the b circuit is R=7.52 as shown in figures from Kirchoff's voltage low simple -9 + 7512- (f-f2)x2 =0 9.512 -20 -99.512=9+21 Iz=19 I -O 9.5 bottom loop from Kirchoff's voltage law in stop loop: (11-12)x2 + 41, -1220 66-212 =12 212=66-12 12 = 31-6 from equation ① and ② CS ScaB C 6 a ( ) +(25) 2 CamScanner

14 = 9+(6x9.5) میوے 66 A 26.5 CSS Web 2.0250 31 g 9.5 9.5 (3x9.5)-2 ges st > 26.51 = 66 → 1 = I 2.49 A .: Iz = 31,-6 ={{3x 2.49)-6)A I = =1:47A i Current through 22 resistor is I, I2 = (2.49-1.47)A » I-I2 =1.02A In terms of mA (4- 12) = 1020mA from ard ohm's law va - Vb = -E + I2R = 9+(1.47x7.5)v