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Which of the following is correct? Solubility = Kw * Ksp. O Ksp is the same as the solubility. O Ksp is an equilibrium consta
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Answer #1

Ksp is an equilibrium constant and is independent of kw .

Using Ksp we can calculate solubility of a solid ,ksp is not solubility.

Solubility gives us the concentration of saturated solution i.e maximum amount that can be dissolved.

So option 3 is correct.

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