Solution:- The normal distribution is symmetric about it
mean
=> The probabilites P(X < c1) = 0.0004, P(X > C2) =
0.0004
The 0.04th and the 99.06th percentile of the standard distribution are -3.35 and 3.35
Hence,
c1 = mu + (Z*sigma)
= 105 + (-3.35*5)
= 88.25
c2 = mu + (Z*sigma)
= 105 + (3.35*5)
= 121.75
The most extreme 0.8% of chloride concentrations value are those
less than 88.25 mmol/L and greater than 121.75 mmol/L
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